Answer:
Conversion of kinetic energy to potential energy (chemo mechanical energy)
In the state of rest, the rubber is a tangled mass of long chained cross-linked polymer that due to their disorderliness are in a state of increased entropy. By pulling on the polymer, the applied kinetic energy stretches the polymer into straight chains, giving them order and reducing their entropy. The stretched rubber then has energy stored in the form of chemo mechanical energy which is a form of potential energy
Conversion of the stored potential energy in the stretched to kinetic energy
By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.
Explanation:
Hydrogen bonds are approximately 5% of the bond strength of covalent C-C or C-H bonds.
Hydrogen bonds strength in water is approximately 20 kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.
20 kJ/350 kJ = 0,057 = 5,7 %.
Answer is: a line containin 7,7e15 cm.
gr(Cu) = 128 pm = 128e-12 m · 10² cm/1 m = 1,28e-8 cm.
n(Cu) = 1 mol.
Na = 6,022e23 1/mol; Avogadro number.
N(Cu) = n(Cu) · Na.
N(Cu) = 1 mol · 6,022e23 1/mol.
N(Cu) = 6,022e23.
l = r(Cu) · N(Cu).
l = 1,28e-8 cm · 6,022e23.
l = 7,7e15 cm.
The solution would be like
this for this specific problem:
Molecular formula of the
two substances: Na2(CO3) and Na(HCO3)
<span>3M * .07L = .21mol </span><span>
<span>1M * .03L
= .03mol </span></span>
<span>.42mol+.03mol = .45mol
Na </span>
30mL + 70mL=100mL or .1L
.45mol/.1L is 4.5M
So the sodium ion concentration is 4.5M. I am hoping that this
answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.
