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Otrada [13]
2 years ago
15

Let x be the number of successes throughout n independent repetitions of a random experiment having probability of success p=1/4

. determine the smallest value of n so that p(1<=x)>=0.7
Mathematics
1 answer:
Llana [10]2 years ago
6 0

To answer problems like this you have to use binomial:

P (x > 1) = 1 – p (0 < x < 1) > .7 

So:

1 – p (0) – p (1) > .7 

1 – (3/ 4) ^n – (3/ 4) ^n (n – 1 ) (1/ 4) > .7 

Therefore n > 5.185, and the smallest value of n so that we can satisfy the given condition is 6 (rounded up)

<span> </span>

You might be interested in
silvia compro la misma licuadora que daniela, que costaba $355.5, pero como abonó con tarjeta de credito, le recargaron un 16%,
Debora [2.8K]

Answer:

Costo final= $412.38

Step-by-step explanation:

Dada la siguiente información:

Costo inicial= $355.5

Recargo de la tarjeta= 16% = 0.16

<u>Para calcular el costo final que debe pagar Silvia, debemos usar la siguiente información:</u>

Costo final= costo inicial*(1 + recargo)

Costo final= 355.5*1.16

Costo final= $412.38

4 0
1 year ago
Simplify: StartRoot 64 r Superscript 8 Baseline EndRoot
patriot [66]

Answer:

  8r^4

Step-by-step explanation:

  \sqrt{64r^8} =\sqrt{(8r^4)^2}=\boxed{8r^4}

5 0
2 years ago
Alayna worked 44 hours last week. Her hourly rate is $9.00. Alayna's gross pay for last week was $
Mama L [17]

44 x 9 = $396.00

It's really that easy to find the answer. Hope you have a nice day!

6 0
2 years ago
Read 2 more answers
In a relay race, each runner completes the circuit 9 seconds faster than the previous one. If the first athlete runs his lap in
Alona [7]

Answer:

31 minutes

Step-by-step explanation:

Here, we have 8 competitors with the previous runner outrunning the present by 9 seconds

1st runner time = 4 minutes 37 seconds

2nd runner time = 4 minutes 37 seconds - 9 seconds = 4 minutes 28 seconds

3rd runner time = 4 minutes 28 seconds - 9 seconds = 4 minutes 19 seconds

4th runner time = 4 minutes 19 seconds - 9 seconds = 4 minutes 10 seconds

5th runner time = 4 minutes 10 seconds - 9 seconds = 4 minutes 1 second

6th runner time s= 4 minutes 1 second - 9 seconds = 3 minutes 52 seconds

7th runner time = 3 minutes 52 seconds - 9 seconds = 3 minutes 43 seconds

8th runner time = 3 minutes 43 seconds - 9 seconds = 3 minutes 34 seconds

The total time is the addition of all the times

For clarity sake, we shall be adding all the minutes together and all the seconds together;

That will be ;

(4 * 6) + 3 minutes + ( 34 + 43 + 52 + 1 + 10 + 19 + 28 + 37)

= 27 minutes + 224 seconds

We need to convert 224 seconds to minutes

Since 60 seconds make one minute; we have

224 - 60(3) = 3 minutes and 44 seconds

Let’s add this to the minutes we had before

That would be;

27 minutes + 3 minutes + 44 seconds

= 30 minutes 44 seconds

since 44 seconds is greater than 1/2 minute (30 seconds), we can approximate it to 1 minute

So the total time is 30 minutes + 1 minute = 31 minutes

8 0
2 years ago
What is the binomial expansion of (x + 2)4? x4 + 4x3 + 6x2 + 4x + 1 8x3 + 24x2 + 32x x4 + 8x3 + 24x2 + 32x + 16 2x4 + 8x3 + 12x2
Margaret [11]

<u>Answer-</u>

\boxed{\boxed{(x+2)^4=x^4+8x^3+24x^2+32x+16}}

<u>Solution-</u>

Given expression is (x+2)^4

Applying Binomial Theorem

\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

Here,

a = x, b = 2 and n = 4

So,

\left(x+2\right)^4=\sum _{i=0}^4\binom{4}{i}x^{\left(4-i\right)}\cdot \:2^i

Expanding the summation

=\dfrac{4!}{0!\left(4-0\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(4-1\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(4-2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(4-3\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(4-4\right)!}x^0\cdot \:2^4

=\dfrac{4!}{0!\left(4\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(3\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(1\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(0\right)!}x^0\cdot \:2^4

=1\cdot x^4\cdot \:1+4\cdot x^3\cdot \:2+6x^2\cdot \:4+4\cdot x\cdot \:8+1\cdot 1\cdot \:16

=x^4+8x^3+24x^2+32x+16

4 0
2 years ago
Read 2 more answers
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