Answer: 957.8
Step-by-step explanation:
To write the function correctly, it is important to assign variables correctly and understand the situation of the problem clearly. For this, we let y the number of people and x as the number of songs played.
At x = 0 y = 567
at x = 1 y = 567 - 567(1/3)
at x = 2 y = 567 - 567(1/3)(1/3)
at x = 3 y = 567 - 567(1/3)(1/3)(1/3)
Therefore, the number of people left after x songs would be represented by the equation:
y = 567 - 567(1/3)x
y = 567 ( 1- x/3 )
To solve this question, you need to find how long jump is. For 2m high with <span>1.67 m/s2 it would be:
h= 1/2 gt^2
2= 1/2 * (1.67) t^2
t^2= 1.67
t= 1.29
If the speed is 20 mph and the jump is 2 second, the distance traveled would be:
20 miles/ hour * 1.29 second * (1 hour/3600second)= 0.007179 miles
If you need to convert it to meter then: </span>0.007179 mile * 1609.34meter/ mile= 11.55 meter
Answer:
840
Step-by-step explanation:
Since the order matters, we use the permutations formula to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
In this question:
The first seat is Jose's.
The remaining four are organized among the other 7 members. So
So the correct answer is:
840
Answer:
1. Take the Average of the distances the ball travelled each hit.
2. He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
3. He should use Mean
4. He should use Median. It best measures skewed data
Step-by-step explanation:
THE FIRST PART.
Raul should take the average of the distances the ball travelled each hit.
This is done by summing the total distances the ball travelled each bounce, and then dividing the resulting value by the total number of times he hit the ball, which is 10.
THE SECOND PART
He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
THE THIRD PART
He should take the mean of the distances of the ball that stayed infield.
This is the distance that occurred the most during the 9 bounces that stayed infield. The one that went outfield is makes it unfair to use any other measure of the center, taking the mean will give a value that is significantly below his efforts.
THE FOURTH PART
He should take the Median of the data, it is best for skewed data.
This is the middle value for all the distances he recorded.
