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Serhud [2]
2 years ago
13

You and a partner tend 3 machines that run continuously. One prints 200 plastic bottles per hour, one prints 180 plastic bottles

per hour, and one prints 150 plastic bottles per hour. If the machines work at their average rates, how many plastic bottles will they print during the 8.5 hours you are at the factory for your shift? a.) 530 b.) 538.5 c.) 1,700 d.) 4,240 e.) 4,505
Mathematics
2 answers:
jarptica [38.1K]2 years ago
7 0
It is e.) 4,505
What you do is each individual times 8.5 then add those together.
Airida [17]2 years ago
5 0
I dont know the answer im just here for points

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The graph shows the speed of a ball in free fall for 10 seconds. Which is the constant of proportionality shown in the graph?
Marizza181 [45]

<u>Given</u>:

The graph shows the speed of a ball in free fall for 10 seconds.

We need to determine the constant of proportionality for the given graph.

<u>Constant of proportionality:</u>

The constant of proportionality can be determined using the formula,

\frac{y}{x}=k

Where k is the constant of proportionality.

Let us consider any of the coordinate from the graph and substitute in the formula.

Consider the coordinate (4,40) and substitute in the above formula.

Thus, we have;

\frac{40}{4}=k

10=k

Thus, the constant of proportionality is 10 meters per second squared.

3 0
2 years ago
Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
Georgia [21]
In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution 


We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ +  v₂c₂
40(0.32) = 10(0.2) + 30c
6 0
2 years ago
Read 2 more answers
What value of x will make this expression equal to 28.1?
Rudiy27
The answer is x=0 I believe because it is the only logical area
5 0
2 years ago
Use the diagram of the right triangle above and round your answer to the nearest hundredth. If m <br> a. 17.32 m<br> b. 6.93 m<b
zepelin [54]
In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m
7 0
2 years ago
Assume there are 365 days in a year.
MissTica

Answer:

1) The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.

Step-by-step explanation:

Given : Assume there are 365 days in a year.

To find : 1) What is the probability that ten students in a class have different birthdays?

2) What is the probability that among ten students in a class, at least two of them share a birthday?

Solution :

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

Total outcome = 365

1) Probability that ten students in a class have different birthdays is

The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

\frac{364}{365}\times \frac{363}{365} \times \frac{362}{365} \times \frac{361}{365}\times\frac{360}{365} \times \frac{359}{365} \times \frac{358}{365} \times \frac{357}{365} \times\frac{356}{365}=0.883

The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday

P(2 born on same day) = 1- P( 2 not born on same day)

\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]

\text{P(2 born on same day) }=1-[\frac{364}{365}]

\text{P(2 born on same day) }=0.002

The probability that among ten students in a class, at least two of them share a birthday is 0.002.

6 0
2 years ago
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