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Basile [38]
2 years ago
9

Which expression is equivalent to b^-2/ab^-3 assume a=0 b=0

Mathematics
2 answers:
PtichkaEL [24]2 years ago
6 0

we have

\frac{b^{-2}} {ab^{-3}}

we know that

\frac{b^{-2}} {ab^{-3}} =(\frac{1}{b^{2}})( \frac{1}{a})( b^{3})\\ \\=\frac{b^{3}}{ab^{2}} \\ \\= \frac{b}{a}

therefore

<u>the answer is the option </u>

\frac{b}{a}

andrey2020 [161]2 years ago
3 0
B^-2/ab^-3 = b^-2/b^-3 x 1/a = b^[-2-(-3)] x 1/a = b x 1/a = b/a
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Answer:

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Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

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\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4

The standard deviation of the sample mean decreased from 0.7 to 0.4 when <em>n</em> is increased from 64 to 196.

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(b)

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So, on decreasing the value of <em>n</em> from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for <em>n</em> = 784 is:

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The standard deviation of the sample mean increased from 0.2 to 0.8 when <em>n</em> is decreased from 784 to 49.

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