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marysya [2.9K]
2 years ago
5

Douring a recent snowstorm, John measured the total snowfall accumulated at the end of each hour. He recorded his results in the

table below Time Snowfall Total 1 p.m. 2 p.m. 3 p.m 4 p.m. 5 p.m. 6 p.m. (in inches) 0.7 1.9 2.8 3 8 4.3 5.1 What is the approximate average rate of change of the snowfall between 1 p.m. and 6 p.m.? !PLEASE HELP!

Mathematics
1 answer:
disa [49]2 years ago
7 0
The average is approximately 3 inches an hour
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ryan had a head start 10 meters

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Noah fills a soap dispenser from a big bottle that contains 2 13 liters of liquid soap. That amount of soap will fill 3 12 dispe
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Answer:

0.68L per dispenser

Step-by-step explanation:

Big bottle contain 213L of soap.

Big bottle will fill 312 dispensers.

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Rectangle TUVW is on a coordinate plane at T (a, b), U (a + 2, b + 2), V (a + 5, b − 1), and W (a + 3, b − 3). What is the slope
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Answer:

The correct option is;

A 1

Step-by-step explanation:

The given rectangle TUVW has coordinates T(a, b), U (a + 2, b + 2), V ( a + 5, b - 1) and W (a + 3, b - 3).

Given that the coordinates of T and U are T (a, b), and U (a + 2, b + 2), we have;

The slope, m of the line TU is is found by the following relation;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where we put (x₁, y₁) = (a, b) and (x₂, y₂) = (a + 2, b + 2), we have;

m = ((b + 2) - b)/((a + 2) - a) = 2/2 = 1

Whereby the slope of a line parallel to another line are equal, we have that the slope of the line parallel to the line that contains the side TU is also 1.

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2 years ago
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Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
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Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

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