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2 years ago

9

If only one external force acts on a particle, does it necessarily change the particle's kinetic energy and velocity? (select al

l that apply.)

1 answer:

ivann1987 [24]2 years ago

7 0

It's necessary to change the particles kinetic and velocity to open external and eternal.

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A small crack occurs at the base of a 15.0-m-high dam. The effective area through which water leaves is 2.30 × 10-3 m2. (a) Igno

vova2212 [387]

Answer

given,

height of the dam = 15 m

effective area of water = 2.3 x 10⁻³ m²

Using energy conservation

$m g h = \dfrac{1}{2}mv^2$

$v= \sqrt{2gh}$

$v= \sqrt{2\times 9.8 \times 15}$

$v= \sqrt{294}$

v = 17.15 m/s

discharge of water

Q = A V

Q = 2.3 x 10⁻³ x 17.15

Q = 0.039 m³/s

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2 years ago

Which actions most likely cause the domains in a ferromagnetic material to align?

Alexxx [7]

Answer:

A ferromagnetic material is a temporary magnet. The domains in a ferromagnetic material are randomly arranged. Under certain actions, the domains align in a particular direction and the material acts as a magnet. The actions that can cause alignment of domains in a ferromagnetic material are:

rubbing the material against a magnet would cause the alignment of domains in the same direction as of the magnet.
passing electricity around the material would generate magnetic field which would cause domains to align along the direction of the field.
placing the material near a strong magnet would cause the alignment of domains in the direction of the field generated by the strong magnet.

Other actions like heating the material, placing the material in a magnetic field of opposite polarity and hitting the material would lead to demagnetization of the magnetic material.

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2 years ago

Read 2 more answers

Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless sur

d1i1m1o1n [39]

Answer:

The speed of bullet and wooden bock coupled together, V = 22.22 m/s

Explanation:

Given that,

Mass of the bullet, m = 0.04 Kg

Mass of the wooden block, M = 0.5 Kg

The initial velocity of the bullet, u = 300 m/s

The initial velocity of the wooden block, U = 0 m/s

The final velocity of the bullet and wooden bock coupled together, V = 0 m/s

According to the conservation of linear momentum, the total momentum of the body after impact is equal to the total momentum before impact.

Therefore,

mV + MV = mu + MU

V(m+M) = mu

V = mu/(m+M)

Substituting the values in the above equation,

V = 0.04 Kg x 300 m/s / (0.04 Kg+ 0.5 Kg)

= 22.22 m/s

Hence, the speed of bullet and wooden bock coupled together, V = 22.22 m/s

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