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Luda [366]
2 years ago
5

When boating in shallow areas or seagrass beds, you see a mud trail in your wake where your boat has churned up the bottom. If y

ou see this trail, you should:
Physics
1 answer:
cluponka [151]2 years ago
7 0

Answer:

when boating in the shallow area or sea grass beds and the mud trail in our wake we should stop our vessel and try to tilt the motor out through the water.

Explanation:

If we see a trail like, when boating in the shallow area or sea grass beds and the mud trail in our wake we should stop our vessel and try to tilt the motor out through the water. And with the help of a pole (or long rod) we should move our vessel out of the shallow water region. If not with pole we should try to walk out our vessel out of the region. since, the running motor of the vessel will attract more problems like clouded water and grass getting stuck in the motor.

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During summer break, Jamie's family went camping in the mountains. There were no roads to their camp, 8 miles away, and it took
liraira [26]

The Answer is B

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2 years ago
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A 1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the cen
NeTakaya

Answer:

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

F_1 + F_2 = W

F_1 + F_2 = (1530\times 9.81)

F_1 + F_2 = 15009.3 N

now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

so we can write torque balance about its center of mass

F_1(1.15) = F_2(2.70 - 1.15)

F_1 = 1.35 F_2

now from above equation

F_2 + 1.35F_2 = 15009.3

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F_2 = 6392.85 N

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F_1 = 8616.45 N

4 0
2 years ago
Calculate the force of Earth’s gravity on a spacecraft 2.00 Earth radii above the Earth’s surface (That would be 3.00 Earth radi
igomit [66]

Answer:

2014.44 N

Explanation:

mass of spacecraft, m = 1850 kg

distance r = 3 x R

where r be the radius of earth.

g be the acceleration due to gravity on the surface of earth and g' be the acceleration due to gravity at height

\frac{g'}{g}=\left (\frac{R}{r}  \right )^{2}

\frac{g'}{g}=\left (\frac{R}{3R}  \right )^{2}

g' = g / 9

g' = 9.8 / 9 = 1.089 m/s²

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Thus, the force of gravity on the space craft at height is 2014.44 N.

3 0
2 years ago
Assuming the same current is running through two separate coils, why is it easier to thrust a magnet into a wire coil with one l
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The magnetic field strength in a coil is directly proportional to the number of turns, or loops, in the coil.
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6 0
2 years ago
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What is the efficiency of a machine if your work on the machine is 1200 j and the machines output work is 300 j?
inysia [295]

Answer:

The efificiency is 0,25 of the machine  (25%). See the explanation below

Explanation:

We calculate the efficiency with this formula:

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