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spayn [35]
2 years ago
10

a chunk of lead at 91.6 C was added to 200.0g of water at 15.5 C. The specific heat of lead is 0.129J/g C. When the temperature

stabilized, the temperature of the mixture was 17.9 C. Assuming no heat was lost to the surroundings, what was the mass of lead added?
Chemistry
1 answer:
worty [1.4K]2 years ago
4 0
Let's apply the conservation of energy through the equation below:

Q for lead + Q for water = 0
So,
Q for lead = -Q for water
where
Q = mass*specific heat*(T₂ - T₁)
The specific heat of liquid water is 4.187 J/g·°C

Substituting the values:
(m)(0.129 J/g·°C)(17.9 - 91.6°C) = -(200 g)(4.187 J/g·°C)(17.9 - 15.5°C)
Solving for m,
m = <em>211.39 grams of lead</em>

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What is the pOH of a solution that has a hydronium ion concentration [H3O+] of 8.26 x 10–5 M
viva [34]

Answer:

The pOH of the solution is 9.92

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance. PH is defined as the negative logarithm (base 10) of the hydronium ion concentration [H₃O⁺]:

pH= - log [H₃O⁺]

So, if [H₃O⁺]=8.26*10⁻⁵, the pH is: pH=- log (8.26*10⁻⁵) ⇒ pH= 4.08

The pOH measures the concentration of OH− ions. The following relationship can be established between pH and pOH:

pH + pOH= 14

In this case, being pH=4.08  and replacing in the relationship between pH and pOH:

4.08 + pOH=14

Solving:

pOH= 14 - 4.08

pOH= 9.92

The pOH of the solution is 9.92

6 0
2 years ago
The reaction A + B → 2 C has the rate law rate = k[A][B]³. By what factor does the rate of reaction increase when [A] remains co
lawyer [7]

Answer:

8

Explanation:

To solve this question, we just need to put the new number into the equation. If [A] remain constant then that mean [A2]= [A1]. If B doubled, then that mean [B2]= 2[B2]. To find what factor does the rate of reaction increases, we need to divide the first reaction rate with the second. The calculation will be:

rate2/rate1= k[A2][B2]³     /     k[A1][B1]³

rate2/rate1= [A1][2B1]³      /     [A1][B1]³

rate2/rate1=  A1*8B1³       /     A1*B1³

rate2/rate1= 8/1= 8

The rate of reaction will be 8 times faster.

7 0
2 years ago
A solution is prepared by dissolving 91.7 g fructose in 545 g of water. Determine the mole fraction of fructose if the final vol
oee [108]

Answer:

Mole fraction = 0,0166

Explanation:

Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.

The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:

91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>

545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>

Thus, mole fraction of fructose is:

\frac{0,509 moles}{0,509mol + 30,24mol} = 0,0166

<em>Mole fraction = 0,0166</em>

I hope it helps!

5 0
2 years ago
2 physical changes that happen in aquaponics
maks197457 [2]

Answer:

The physical and chemical change that occurs in the aquaponics are given below.

Explanation:

The plants and animals grow in size and decrease the mass of plant due to eating by the fishes is a physical changes which occurs in aquaponics. The sunlight has a heat energy which is absorb by the plants present in aquaponics which is a type of endothermic reaction. In aquaponics, the ammonia present in water is converted into nitrates which is used by the plants as a nutrients. When the mass is converted into energy, it increases the temperature of the ecosystem and also the earth surface. For example, if a wood is burn, it change into heat energy which increases the temperature and cause the global warming on the earth surface.

3 0
2 years ago
24 how many moles are in 2.04 × 1024 molecules of h2o?
Sergeeva-Olga [200]
The answer is 3.39 mol.

<span>Avogadro's number is the number of molecules in 1 mol of substance.
</span><span>6.02 × 10²³ molecules per 1 mol.
</span>2.04 × 10²⁴<span> molecules per x.

</span>6.02 × 10²³ molecules : 1 mol = 2.04 × 10²⁴ molecules : x
x = 2.04 × 10²⁴ molecules * 1 mol : 6.02 × 10²³ molecules
x = 2.04/ 6.02 × 10²⁴⁻²³ mol
x = 0.339 × 10 mol
<span>x = 3.39 mol
</span>
8 0
2 years ago
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