<span>The answer to this question would be: (3) The ice cube gains heat energy and the water loses heat energy.
Based on the law of conservation of energy, the energy in an isolated system should be constant. If something receives energy, other must be losing energy. The option 1 and 2 definitely false because the total energy is not constant.
In this case, the ice should have lower heat energy, so the ice should be the one who receives energy from the water</span>
C6H6 + 02 forms CO2 + H20
Complete with factors to stabilize
C6H6 + 15/2 O2 forms 6 CO2 + 3 H2O
You take away only the info you need
C6H6 15/2 O2
1 mol 15/2 or 7,5 mol
15/2 or 7,5 mol of O2 are required.
;)
Answer:
P(total) = 1110 mmHg
Explanation:
According to the Dalton law of partial pressure,
The pressure exerted by mixture of gases are equal to the sum of partial pressure of individual gases.
P(total) = P1 + P2 + P3+ .....+ Pn
Given data:
Sample A = 740 mmHg
Sample B = 740 mmHg
Sample C = 740 mmHg
Total pressure = ?
Solution:
<em>Sample A:</em>
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 740 mmHg × 2L/4L
P₂ = 370 mmHg
<em>Sample B:</em>
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 740 mmHg × 2L/4L
P₂ = 370 mmHg
<em>Sample C:</em>
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 740 mmHg × 2L/4L
P₂ = 370 mmHg
Total pressure:
P(total) = P1 + P2 + P3
P(total) = 370 mmHg + 370 mmHg+ 370 mmHg
P(total) = 1110 mmHg
Answer:
captive breeding would help the best
Hmm. I'm not 100% sure but. I'm pretty sure it's A because the heated water is below and there's a hotter temp. Also because it's copper, heat will move more quickly. I'm not 100% sure, are there notes you can check?
