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2 years ago

A molecule of Al2(SO4)3 contains: 12 O atoms 4 O atoms 6 Al atoms 12 S atoms

Chemistry

2 answers:

AleksAgata [21]2 years ago

8 0

Answer is: A molecule of Al2(SO4)3 contains 12 O.

Al₂(SO₄)₃ is salt aluminium sulfate.

Aluminium sulfate contains:

1) two aluminium atoms (Al).

2) three sulfur atoms (S).

3) twelve oxygen atoms (O). There are three sulfate anions (SO₄²⁻) and every anion contains four oxygen and one sulfur atom.

Aluminium has oxidation number +3 and sulfate has charge -2.

solmaris [256]2 years ago

7 0

12 O atoms
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Write a balanced half-reaction for the oxidation of liquid water H2O to aqueous hydrogen peroxide H2O2 in basic aqueous solution

nignag [31]

Answer : The balanced half-reaction in a basic solution will be,

$2OH^-(aq)\rightarrow H_2O_2(aq)+2e^-$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Rules for the balanced chemical equation in basic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion $(OH^-)$ at that side where the less number of hydrogen are present.

Now balance the charge.

The half reaction is :

$H_2O(l)\rightarrow H_2O_2(aq)$

Now balance the oxygen atoms.

$H_2O(l)\rightarrow H_2O_2(aq)+H_2O(l)$

Now balance the hydrogen atoms.

$H_2O(l)+2OH^-(aq)\rightarrow H_2O_2(aq)+H_2O(l)$

Now balance the charge.

$H_2O(l)+2OH^-(aq)\rightarrow H_2O_2(aq)+H_2O(l)+2e^-$

The balanced half-reaction in a basic solution will be,

$2OH^-(aq)\rightarrow H_2O_2(aq)+2e^-$

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2 years ago

the half-life of a certain radioactive element is 1250 years. what percent of the atom remains after 7500 years?

Olenka [21]

Maybe 24% not sure try researching it on google

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2 years ago

Silver chloride is formed by mixing silver nitrate and barium chloride solutions. What volume of 1.50 M barium chloride solution

konstantin123 [22]

Answer:

1.22 mL

Explanation:

Let's consider the following balanced reaction.

2 AgNO₃ + BaCl₂ ⇄ Ba(NO₃)₂ + 2 AgCl

The molar mass of silver chloride is 143.32 g/mol. The moles corresponding to 0.525 g are:

0.525 g × (1 mol/143.32 g) = 3.66 × 10⁻³ mol

The molar ratio of AgCl to BaCl₂ is 2:1. The moles of BaCl₂ are 1/2 × 3.66 × 10⁻³ mol = 1.83 × 10⁻³ mol.

The volume of 1.50 M barium chloride containing 1.83 × 10⁻³ moles is:

1.83 × 10⁻³ mol × (1 L/1.50 mol) = 1.22 × 10⁻³ L = 1.22 mL

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2 years ago

If a sample containing 2.50 ml of nitroglycerin (density=1.592g/ml) is detonated, how many total moles of gas are produced?

masya89 [10]

<span>0.127 moles The formula for nitroglycerin is C3H5N3O9 so let's first calculate the molar mass of it. Carbon = 12.0107 Nitrogen = 14.0067 Hydrogen = 1.00794 Oxygen = 15.999 C3H5N3O9 = 3 * 12.0107 + 5 * 1.00794 + 3 * 14.0067 + 9 * 15.999 = 227.0829 Now calculate the number of moles of nitroglycerin you have by dividing the mass by the molar mass 2.50 ml * 1.592 g/ml / 227.0829 g/mol = 0.017527 mol The balanced formula for when nitroglycerin explodes is 4 C3H5N3O9 => 12 CO2 + 10 H2O + O2 + 6 N2 Since all of the products are gasses at the time of the explosion, there is a total of 29 moles of gas produced for every 4 moles of nitroglycerin Now multiply the number of moles of nitroglycerin by 29/4 0.017527 mol * 29/4 = 0.12707075 moles Round to 3 significant figures, giving 0.127 moles</span>

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2 years ago

A quantity of 85.0 mL of 0.900 M HCl is mixed with 85.0 mL of 0.900 M KOH in a constantpressure calorimeter that has a heat capa

bogdanovich [222]

Explanation:

The given data is as follows.

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