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stich3 [128]
2 years ago
12

Difference of squares gives which complex factors for the expression x^2+13

Mathematics
2 answers:
Serga [27]2 years ago
7 0

The Given Expression is : → x² + 13

  =  x² + (√13)²

=  x² - ( i √13)²  As , i²= -1 because , i = √-1

= (x - i√13)(x +√13)   → Using the formula , A² - B² = (A-B)(A+B)

Out of the four options Given : Option C →(x - i√13)(x +√13) is true regarding the expansion of function x² + 13.

fredd [130]2 years ago
7 0

Answer:

Option C.

Step-by-step explanation:

Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

Now we have to factorize it.

(x² + 13) = x² + (√13)²

             = x² + [-(i)²√(13)²]  [Since i = √(-1)]

             = x² - (i√13)²

             = (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]

Option C will be the answer.

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During a certain week, a post office sold Rs.280 worth of 14-paisas stamps. How many of these stamps did they sell?
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You convert the rupees in paisas. One rupee is equal to one hundred paisas, so ...

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a lunch stand makes a $.75 profit on each chef's salad and $1.20 profit on each caesar salad. On a typical weekday, it sells bet
tangare [24]

Answer:

<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>

Step-by-step explanation:

Suppose, the number of Chef's salad is x and the number of Caesar salad is y

On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.

So, the two constraints are:  40\leq x\leq 60 and  35\leq y\leq 50

The total number sold has never exceed 100 salads. So, another constraint will be:   x+y\leq 100

According to the graph of the constraints, the vertices of the common shaded region are:  (40,35), (60,35), (60,40), (50,50) and (40,50)   <em>(Refer to the attached image for the graph)</em>

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be:  P=0.75x+1.20y

For  (40, 35) ,   P=0.75(40)+1.20(35)=72

For  (60, 35) ,   P=0.75(60)+1.20(35)=87

For  (60, 40) ,   P=0.75(60)+1.20(40)=93

For  (50, 50) ,   P=0.75(50)+1.20(50)=97.5 <u><em>(Maximum)</em></u>

For  (40, 50) ,   P=0.75(40)+1.20(50)=90

Profit will be maximum when x=50 and y=50

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

6 0
2 years ago
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