The probability that a freshman student at this school plays either a sport or a musical instrument is 0.74
Step-by-step explanation:
The addition rules in probability are:
- P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen at the same time)
- P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they have at least one outcome in common)
∵ The probability that a freshman plays a sport is 0.55
∴ P(sport) = 0.55
∵ The probability that a freshman plays a musical instrument is 0.34
∴ P(music) = 0.34
∵ The probability that a freshman plays both a sport and a musical
instrument is 0.15
∴ P(sport and music) = 0.15
To find the probability that freshman student at this school plays either a sport or a musical instrument use the second rule above because it is non-mutually exclusive
∵ P(sport or music) = P(sport) + P(music) - P(sport and music)
∴ P(sport or music) = 0.55 + 0.34 - 0.15
∴ P(sport or music) = 0.74
The probability that a freshman student at this school plays either a sport or a musical instrument is 0.74
Learn more:
You can learn more about the probability in brainly.com/question/9178881
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Answer:
Value of v that minimizes E is v = 3u/2
Step-by-step explanation:
We are given that;
E(v) = av³L/(v-u)
Now, using the quotient rule, we have;
dE/dv = [(v-u)•3av²L - av³L(1)]/(v - u)²
Expanding and equating to zero, we have;
[3av³L - 3av²uL - av³L]/(v - u)² = 0
This gives;
(2av³L - 3av²uL)/(v-u)² = 0
Multiply both sides by (v-u)² to give;
(2av³L - 3av²uL) = 0
Thus, 2av³L = 3av²uL
Like terms cancel to give;
2v = 3u
Thus, v = 3u/2
2(1.25x+3)=23.5
2.5x+6=23.5
