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snow_tiger [21]
2 years ago
14

A series circuit contains three 2 Ω resistors and a 6 Ω resistor. The current in each resistor is 4.0 A. What is the voltage of

the battery in the circuit? 2.0 V 3.0 V 32 V 48 V
Physics
2 answers:
Andrej [43]2 years ago
9 0

Answer:

48

Explanation:

i just took the test

allochka39001 [22]2 years ago
6 0

The effective resistance of several resistors in series
is the sum of their individual resistances.

In this circuit, the effective resistance is 

                (2 ohms + 2 ohms + 2 ohms + 6 ohms)  =  12 Ω .

So  12 ohms  is what the battery sees.  The battery doesn't know
whether that's a single resistor, or the sum of several.


Now, the voltage across a resistor is

                     V  =  (current) · (resistance) .

For this circuit ...

                      V  =  (4.0 A) (12 Ω)  =  48 volts .
You might be interested in
The velocity of a 10.0 kg object that has 720 J of kinetic energy is m/s. (Report the answer to two significant figures.)
nikdorinn [45]
Kinetic energy<span> is the </span>energy<span> of motion. An object that has motion - whether it is vertical or horizontal motion - has </span>kinetic energy<span>. It is expressed as:

KE = mv^2 /2

720 = 10.0v^2 /2
v = 12 m/s

Hope this answers the question. Have a nice day.</span>
4 0
2 years ago
Read 2 more answers
A stone is thrown vertically upward with a speed of 15.0 m/s from the edge of a cliff 75.0 m high.How much later does it reach t
Katarina [22]

Answer:

5.72 seconds

848.27 m/s

97.94 m

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=15-9.81\times t\\\Rightarrow \frac{-15}{-9.81}=t\\\Rightarrow t=1.52 \s

Time taken to reach maximum height is 0.97 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=15\times 1.52+\frac{1}{2}\times -9.81\times 1.52^2\\\Rightarrow s=11.47\ m

So, the stone would travel 11.47 m up

So, total height stone would fall is 75+11.47 = 86.47 m

Total distance travelled by the stone would be 75+11.47+11.47 = 97.94 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 86.47=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{86.47\times 2}{9.81}}\\\Rightarrow t=4.2\ s

Time taken by the stone to travel 86.47 m to the water is is 4.2 seconds

The stone reaches the water after 4.2+1.52 = 5.72 seconds after throwing the stone

v=u+at\\\Rightarrow v=0+9.81\times 86.47 = 848.27\ m/s

Speed just before hitting the water is 848.27 m/s

3 0
2 years ago
A 25 gram bullet is fired from a gun with a speed of 230 m/s. If the gun has a mass of 0.9 kg what is the recoil speed of gun ?
Step2247 [10]

Given data:

mass of the bullet (m) = 25 g = 0.025 kg,

mass of the gun    (M) = 0.9 kg,

speed of the bullet (v) =230 m/s,

speed of the bullet (V) = ?

From the given data it is clear that, the momentum is conserved. According to "<em>law of conservation of momentum" </em>the total momentum before and after the collision is equal.

In this problem the momentum before collision (bullet+gun) is zero.

Therefore, after the gun fires a bullet, the momentum must be zero.

Mathematically,

          M × V + m × v = 0

           where,

                     M × V = momentum of the gun

                     m × v = momentum of the bullet

            (0. 9 × V) + (0.025 × 230) = 0

             0.9 V = -5.75

                    V = -5.75/0.9

                        = -6.39 m/s  

<em>The gun recoils with a speed of 6.39 m/s</em>

8 0
2 years ago
For a Physics course containing 10 students, the maximum point total for the quarter was 200. The point totals for the 10 studen
Talja [164]

Answer:

130.5

Explanation:

According to the stemplot attached (Which I think it is, and if not, then you only need to replace the procedure with your data and you should be fine), you need to calculate first the points of all ten students. In that plot, we can easily calculate the points.

The first number in the colum represents the centen of the point, while the numbers of the second column, represents the units of that centen, for example if you see:

16 | 8 5 6

This means that the point for the students are 168, 165 and 166. Three students, three points.

If you watch the stemplot, the points for the students are:

116, 118, 121, 124, 128, 133, 137, 142, 146 and 179.

The median can be calculated using the mean between the two values in the middle of the sequence.

In this case, half of ten is 5, so, the numbers from the middle in this sequence are 128 and 133, therefore:

Median = 128 + 133 / 2 = 130.5

5 0
2 years ago
Kimonoski takes a 9-minute shower every day. The shower uses about 1.8 gal per minute of water. He also uses 23 gallons of hot w
ioda

Answer:

Q_{week} = 458884.6\, BTU

Explanation:

The weekly water consumption of Kimonoski is:

m_{bath,week} = (62.4\,\frac{lbm}{ft^{3}})\cdot (1.8\,\frac{gal}{min} )\cdot (\frac{0.134\,ft^{3}}{1\,gal} )\cdot (\frac{1\,min}{60\,s} )\cdot (9\,min)\cdot (\frac{60\,s}{1\,min} )\cdot (7\,\frac{days}{week} )\cdot (1\,week)

m_{bath.week} = 948.205\,lbm

m_{others, week} = (62.4\,\frac{lbm}{ft^{3}})\cdot (23\,gal)\cdot (\frac{0.134\,ft^{3}}{1\,gal} )\cdot (7\,\frac{days}{week} )\cdot (1\,week)

m_{others, week} = 1346.218\,lbm

m_{week} = m_{bath,week} + m_{others, week}

m_{week} = 2294.423\,lbm

The total energy required per week for hot water is:

Q_{week} = m_{week}\cdot c_{p,water}\cdot \Delta T

Q_{week} =(2294.423\,lbm)\cdot (1\,\frac{BTU}{lbm\cdot ^{\textdegree}F} )\cdot (50^{\textdegree}F)

Q_{week} = 458884.6\, BTU

3 0
2 years ago
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