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Pachacha [2.7K]
2 years ago
4

When is the zebra in motion?

Physics
1 answer:
zavuch27 [327]2 years ago
3 0
The zebra is stationary(not moving) when the gradient of the distance/time graph is zero; between 20 and 40 seconds. The zebra is moving away from the origin when the gradient is positive; between 0 and 20 and 40 and 60 seconds. Average speed is the distance travelled/ time elapsed so the average speed is 280/60 = 4.67 m/s
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Which of the following is not a factor in whether a reaction will spontaneously occur? A. Entropy change of the system B. Enthal
Delvig [45]

Answer:

D

Explanation:

pressure change have nothing to do with the spontaneity.

Entropy change , enthalpy change , temperature have roles in deciding spontaneity.

6 0
2 years ago
1. A student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.
Snezhnost [94]

Explanation:

(a) Displacement of an object is the shortest path covered by it.

In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.  She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.

0.4 miles = 0.64 km

displacement = 0.7-0.3+0.64 = 1.04 km

(b) Average velocity = total displacement/total time

t = 15 min = 0.25 hour

v=\dfrac{1.04\ km}{0.25\ h}\\\\v=4.16\ km/h

Hence, this is the required solution.

8 0
2 years ago
What units are given to the right of the equals sign
zhuklara [117]
The answer

2y + 14 = 17

The 17 is to the right of the = sign
It is also the answer
7 0
2 years ago
Four wrestlers step on a scale for a tournament. Wrestler A weighs in at 170 pounds; wrestler B weighs in at 168 pounds; wrestle
OLga [1]
The force due to gravity is equal to the product of the mass and acceleration due to gravity. Since the acceleration due to gravity is constant, we just have to rely on the comparison of their masses to determine the mass effect. Thus, the answer to this item is Wrestler C weighing 171 pounds. 
7 0
2 years ago
Read 2 more answers
A student releases a block of mass m from rest at the top of a slide of height h1. The block moves down the slide and off the en
Nina [5.8K]

Answer:

B)   d = √  ( 4 h₂ ( H - 2h₂))

Explanation:

A) 1) If the height of the slide is very small, there is no speed to leave the table, therefore do not recreate almost any horizontal distance

2) If the height is very small downwards, it touches the earth a little and the horizon is small,

B) to find an equation for horizontal distance (d)

We must maximize the speed at the bottom of the slide let's use energy

Starting point Higher

         Em₀ = U = m g h₁

Final point. Lower (slide bottom)

           Emf = K + U = ½ m v² + m gh₂

As there is no friction the energy is conserved

            mgh₁ = ½ m v² + mgh₂

            v² = 2 g (h₁-h₂)

This is the speed with which the block leaves the table, bone is the horizontal speed (vₓ)

The distance traveled when leaving the table can be searched with kinematics, projectile launch

          x = v₀ₓ t

         y =  t - ½ g t²

The height is the height of the table (y = h₂), as it comes out horizontally the vertical speed is zero

        t = √ 2h₂ / g

We substitute in the other equation

        d = √ (2g (h₁-h₂))  √ 2h₂ / g

        d = √ (4 h₂ (h₁-h₂))

        H = h₁ + h₂

        h₁ = H -h₂

        d = √  ( 4 h₂ ( H - 2h₂))

Explanation:

7 0
2 years ago
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