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Hatshy [7]
1 year ago
9

Selina and three of her classmates each wrote out the steps for finding an approximate percent change. They all agreed on the fi

rst and fourth step:
1. Find the positive difference between the original number and the new number.
2. ________________________
3. ________________________
4. Round the answer if necessary.

They did not agree on steps 2 and 3. Which instructions are correct for steps 2 and 3?
Mathematics
2 answers:
Naddik [55]1 year ago
5 0

Answer: 2. Divide the difference by the original number.

3. Multiply it by 100.

Step-by-step explanation:

Since when we find the percentage change in a number then we follow the following steps,

1. find the difference between the new number and the original number.

2. divide the difference by the original number.

3. Multiply it by 100.

4.Round the answer if necessary.

We can understand it with help of the below example.

If a number 25 changes to 75.

Then the percentage change in 25 = \frac{75-25}{25} \times 100=\frac{50}{25}\times 100 = 200%

kotegsom [21]1 year ago
3 0
Step 2 is divide the difference between the original number and the new number by the original number. you will get a decimal.

step 3 convert what you got from step 2 to a percent by multiplying it by 100 and adding %
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You receive an email asking you to forward it to four other people to ensure prosperity. Assuming the chain isn't broken, how ma
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A restaurant has a special whereby both parents can eat for $20 and each child can eat for $5. Assuming a family group consists
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4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln
pochemuha

Answer:

No these these result do not differ at 95% confidence level  

Step-by-step explanation:

From the question we are told that

  The first concentrations is  c _1= 30.0 \ g/m^3

      The second concentrations is  c _2 = 52.9 \ g/m^3

  The first sample size is  n_1 =  32

    The second sample size is  n_2 =  32

   The  first standard deviation is \sigma_1 =  30.0

     The  first standard deviation is \sigma_1 =  29.0

The mean for  Turnpike is  \= x _1 = \frac{c_1}{n}  =  \frac{31.4}{32} = 0.98125

The mean for   Tunnel is  \= x _2 = \frac{c_2}{n}  =  \frac{52.9}{32} = 1.6531

The  null hypothesis is  H_o  :  \mu _1 - \mu_2  =  0

The  alternative hypothesis is  H_a  :  \mu _1 - \mu_2  \ne  0

Generally the test statistics is mathematically represented as

              t =  \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1}  +\frac{\sigma_2^2}{n_2} }}

         t =  \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32}  +\frac{29^2}{32} }}

        t = - 0.0899

Generally the degree of freedom is mathematically represented as

     df =  32+ 32 - 2

     df =  62

The  significance \alpha  is  evaluated as

      \alpha  =  (C - 100 )\%

=>   \alpha  =  (95 - 100 )\%

=>   \alpha  =0.05

The  critical value  is evaluated as

      t_c  =  2  *  t_{0.05 ,  62}

From the student t- distribution table  

        t_{0.05, 62} =  1.67

So

     t_c  =  2 * 1.67

=>  t_c  = 3.34

given that

       t_c  >  t we fail to reject the null hypothesis so  this mean that the result do  not differ

       

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