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PtichkaEL [24]
1 year ago
10

Mike has a net spendable income of $1,400. He decides to set up a budget before looking for an apartment or a car. He sets up hi

s budget and finds that he has lots of money left over. He puts the extra money into entertainment. Housing $420 Food $168 Transportation $210 Insurances $42 Debts $70 Entertainment $224 Clothing $70 Savings $70 Medical $56 Miscellaneous $70 Why might this budget be a problem? Mike will spend more money than he is earning. Mike does not have enough money budgeted for food or medical expenses. Mike is using the minimum recommended percentages for food, housing, and transportation. The costs are likely to exceed the expenses in each category. Mike has not budgeted all of his money. He will find that he has extra money at the end of the month, which will end up being wasted. NextReset
Mathematics
1 answer:
KATRIN_1 [288]1 year ago
3 0
This budget might be a problem because Mike is using the minimum recommended percentages for food, housing, and transportation. He prepared the biggest sum for entertainment, putting the basic needs under the disadvantage and forgetting about medical emergencies. Therefore, in the end of month there is a strong possibility that he will find out he organized his budget in a wrong way. 
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Answer:

Option E

Step-by-step explanation:

This survey will not be reliable as it is chosen for convenience; the first 120 students to arrive in school on a particular morning and this collection of individuals may not be a representative of the population. The study may become biased because it does not take into account the latecomers among the students which might have been changed the study from systematically favoring certain outcomes.

5 0
1 year ago
Robert earned $10, which was 4 less than twice what Eric earned , How much money did Eric earn?
Kisachek [45]

Answer:

Eric's earning is $7

Step-by-step explanation:

Given

Represent Robert's earnings with R and Eric's with E.

R = 10\\R = 2E - 4

Required

What is the value of E?

Substitute 10 for R in the second equation.

10 = 2E - 4

Solve for 2E

2E = 10 + 4

2E = 14

Solve for E

E = 14/2

E = 7

<em>Eric's earning is $7</em>

6 0
2 years ago
The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) = (e^-x/1076)/
kozerog [31]

Answer:

(a) 0.06154

(b) 0.2389

(c) 0.6052

(d) 2478

Step-by-step explanation:

probability density function of the time to failure of an electronic component in a copier (in hours) is

P(x) = 1/1076e^−x/1076

λ = 1/1076

A) A component lasts more than 3000 hours before failure:

P(x>3000) = 1 − e^−3000/1076

= 0.06154

B) A component fails in the interval from 1000 to 2000 hours:

P(1000>x>2000) =1 − e^−2000/1076 − 1 +e^−1000/1076 = e^−1000/1076 − e^−2000/1076 = 0.3948 − 0.1559

= 0.2389

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P(x<1000) = 0.6052

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e^−x/1076 = 0.1

= −x/1076

= ln(0.1)

x =(2.3026)×(1076)

x = 2478

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Step-by-step explanation:

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