Answer:
A
Step-by-step explanation:
Just took the quiz on edgenuity
Answer:
7.5 seconds.
Step-by-step explanation:
Substitute the distace 220m in the given equation:
d = 19t + t^2
200 = 19t + t^2
t^2 + 19t - 200 = 0
t = [-19 +/- sqrt(19^2 - 4*1*-200)] / 2
t = -19 +/- sqrt(1161) / 2
t = ( -19 +/- 34.07) / 2
t = 7.535 seconds
The answer is
<span>a) 1000=-16t^2+1700, implies t² = -700 /-16, and t= 6.61s
b) </span><span>970= -16t^2+1700, </span><span>implies t² = -730 /-16, and t=6.75s
c)
reasonable domain of h
h is polynomial function, so its domain is R, (all real number)
its range
the inverse of h is h^-1 = sqrt (1700- t / 16), and its domain is </span>
<span><span><span>1700- t / 16>=0, so t <1700,
the range of h is I= ]-infinity, 1700]</span> </span> </span>
we know that
The measure of the interior angle is the half-sum of the arcs comprising it and its opposite.
so
<u>Find the measure of the angle LAM</u>
m∠LAM is equal to
![\frac{1}{2}*[arc\ KJ+arc\ LM]= \frac{1}{2}*[170+80]\\\\=125\ degrees](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2A%5Barc%5C%20KJ%2Barc%5C%20LM%5D%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%5B170%2B80%5D%5C%5C%5C%5C%3D125%5C%20degrees)
<u>Find the measure of the angle MAJ</u>
we know that
m∠LAM+m∠MAJ=
° ------> by supplementary angles
m∠MAJ=
m∠MAJ=
°
therefore
<u>the answer is</u>
The measure of the angle MAJ is 
Answer:
He set the compass on a, with the width slightly wider than the distance to o and drew an arc above and below o. He then set the compass on b, without changing the width on the compass and did the same thing. True
He drew a line through where the arc pairs intersected and then labeled the points where this line crossed the top and bottom of the original circle. True
He set the compass on o, with the width slightly wider than the distance to b, and he drew a slightly larger circle around the original circle. False
He used the points that were marked along the circumference of the original circle as the vertices for the square. True
Step-by-step explanation:
Performance matters test perhaps?