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2 years ago

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Which statements are part of the safety protocol for this lab experiment? Check all that apply. Always wear safety goggles when

performing an experiment. Use caution when constructing the track. Pad cars with foam prior to each trial. Ensure that the track is clear before releasing cars. Bolt the ramp to both the floor and desk for support. Report all accidents to the teacher.

2 answers:

djyliett [7]2 years ago

8 0

 Always wear safety goggles when performing an experiment, especially with objects in motion.

 Make sure you understand the proper use and assembly of the cart, track, and sensors.

 Use caution when assembling and adjusting the dynamics track. Dynamics tracks may have sharp

edges or other parts that may pinch hands or fingers.

 Behavior in the lab needs to be purposeful.

 Report all accidents–no matter how big or small–to your teacher

mr_godi [17]2 years ago

4 0

Answer:

Always wear safety goggles when performing an experiment.

Use caution when constructing the track.

Ensure that the track is clear before releasing cars.

Report all accidents to the teacher.

Explanation:

I just did this ;)

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49. A vertically hung 0.50-meter- long spring is stretched from its equilibrium position to a length of 1.00 meter by a weight a

Natali5045456 [20]

Answer:

$K=120$

Explanation:

From the question we are told that

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Length of stretched $l_s=1m$

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Generally equation for energy stored is mathematically given as

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$K=\frac{2U}{\triangle x^2}$

$K=\frac{2*15}{ 0.5^2}$

Therefore value of the spring constant in N/m? is given as

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1 year ago

A 0.10 kg piece of copper at an initial temperature of 95°c is dropped into 0.20 kg of water contained in a 0.28 kg aluminum cal

DedPeter [7]

<span>(cp of Copper = 387J / kg times degrees C; cp of Aluminum = 899 J / kg times degrees C; cp of Water = 4186J / kg times degrees C)
</span> Use the law of conservation of energy and assuming no heat loss to the surroundings, then
<span>Heat given up by copper = heat absorbed by water + heat absorbed by calorimeter
</span><span> Working formula is
</span> <span>Q = heat = MCp(delta T)
</span><span> where
</span><span> M = mass of the substance
</span><span> Cp = specific heat of the substance
</span><span> delta T = change in temperature
</span> Heat given up by copper = 0.10(387)(95 - T)
<span> Heat absorbed by water = 0.20(4186)(T - 15)
</span><span> Heat absorbed by calorimeter = 0.28(899)(T - 15)
</span> where
<span> T = final temperature of the system
</span><span> Substituting appropriate values,

</span> 0.10(387)(95 - T) = 0.20(4186)(T - 15) + 0.28(899)(T - 15)
<span> 38.7(95 - T) = 1088.92(T - 15)
</span><span> 3676.50 - 38.7T = 1088.92T - 16333.8
</span><span>1127.62T = 20010.3
</span><span> T = 17.75 C </span>

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2 years ago

An individual white LED (light-emitting diode) has an efficiency of 20% and uses 1.0 W of electric power. a. How many LEDs must

Neporo4naja [7]

Answer:

8, 8 W

Explanation:

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$0.2\times 1=0.2\ W$

Total power required is 1.6 W

Number of Light Emitting Diodes would be

$n=\dfrac{1.6}{0.2}\\\Rightarrow n=8$

The number of Light Emitting Diodes is 8.

Power would be

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2 years ago

The graph indicates Linda’s walk.

Sedaia [141]

I think the right answer is the first one. If she stops moving her Position does not change any more-and the Graph Shows that after 6 seconds she stays at the Position of 5 m. If she Went Back to the start point the Graph would have Developed Back to 0m(decreased).

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2 years ago

Read 2 more answers

Suppose two astronauts on a spacewalk are floating motionless in space, 3.0 m apart. Astronaut B tosses a 15.0 kg IMAX camera to

marta [7]

Answer:

$\frac{ 112.5}{15+m_{A}}=v_{f}$

(we need the mass of the astronaut A)

Explanation:

We can solve this by using the conservation law of the linear momentum P. First we need to represent every mass as a particle. Also we can simplify this system of particles by considering only the astronaut A with an initial speed $v_{iA}$ of 0 m/s and a mass $m_{A}$ and the IMAX camera with an initial speed $v_{ic}$ of 7.5 m/s and a mass $m_{c}$ of 15.0 kg.

The law of conservation says that the linear momentum P (the sum of the products between all masses and its speeds) is constant in time. The equation for this is:

$P_{i}=p_{ic}+p_{iA}\\P_{i}=m_{c}v_{ic}+m_{A} v_{iA}\\P_{i}=15*7.5 + m_{A}*0\\P_{i}=112.5 \frac{kg.m}{s}$

By the law of conservation we know that $P_{i} =P_{f}$

For $P_{f}$ (final linear momentum) we need to treat the collision as a plastic one (the two particles stick together after the encounter).

So:

$P_{i} =P_{f}=112.5\\$

$112.5=(m_{c}+m_{A})v_{f}\\\frac{ 112.5}{m_{c}+m_{A}}=v_{f}\\\frac{ 112.5}{15+m_{A}}=v_{f}$

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2 years ago