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saw5 [17]
2 years ago
4

An automobile engine is 2.60 liters how many cubic inches is this

Chemistry
2 answers:
Lapatulllka [165]2 years ago
8 0

Answer: \text{ 2.60 liters }\approx158.66\ \text{ cubic inches}^

Explanation:

We know that  1 inch = 2.54 centimeters

By using UNITARY METHOD,

\text{1 cm}=\dfrac{1}{2.54}\ \text{ in}

Then, \text{1 cm}^3=(\dfrac{1}{2.54})^3=\dfrac{1}{16.387064}\ \text{ in}^3

\text{1000 cm}^3=1000\times\dfrac{1}{16.387064}=61.0237440947\ \text{ in}^3

Since  \text{ 1 liter =}1000\ cm^3

Then, \text{ 1 liter =}61.0237440947\ \text{ in}^3

\text{ 2.60 liters =}2.60\times61.02=158.661734646\approx158.66\ \text{ in}^3

Hence, \text{ 2.60 liters }\approx158.66\ \text{ cubic inches}^

valentinak56 [21]2 years ago
5 0
Capacity is the measure of an object's ability to hold a substance such as solid or fluids (gases and liquids) while volume is the amount of space occupied by an object. Volume is measured is cubic meters, cubic centimeters, cubic inches among other measurements and capacity is measured in liters, milliliters e.t.c.
1 liters is equivalent to 61.0237 cubic inches,
Therefore, 2.6 liters will be equivalent to 2.6 × 61.0237 = 158.6616 cubic inches
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Salt in crude oil must be removed before the oil undergoes processing in a refinery. The
irina1246 [14]

Answer:

\large \boxed{0.64 \, \%}

Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}

2. Calculate the mass of salt in the salty oil

\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}

3. Calculate the mass of salt in the spent water

\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}

4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g  

5. Concentration of salt in washed oil

\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}

3 0
2 years ago
Write the net ionic equation for the reaction of zinc metal with aqueous iron(II) nitrate. Include physical states.
kotykmax [81]

Answer:

Zn°(s) + Fe⁺²(aq)  => Zn⁺²(aq) + Fe°(s)

Explanation:

Molecular Equation:

Zn°(s) + Fe(NO₃)₂(aq) => Zn(NO₃)₂(aq) + Fe°(s)

Ionic Equation:

Zn°(s) + Fe⁺²(aq) + 2NO₃⁻(aq) => Zn⁺²(aq) + 2NO₃⁻(aq) + Fe°(s)

Net Ionic Equation: => Drop NO₃⁻ as spectator ion

Zn°(s) + Fe⁺²(aq)  => Zn⁺²(aq) + Fe°(s)

7 0
2 years ago
Alka‑Seltzer is marketed as a remedy for stomach problems, such as heartburn or indigestion, and pain relief. It contains aspiri
Papessa [141]

Answer:

The equation for the reaction of one sodium bicarbonate ( NaHCO3 ) molecule with one citric acid (C6H8O7) molecule is the following:

Sodium Bicarbonate + Citric Acid ⇒ Water + Carbon Dioxide + Sodium Citrate

NaHCO3 + C6H8O7 ⇒ 3 CO2 + 3 H2O + Na3C6H5O7

Explanation:

The reaction is in balance, that is, the whole H2CO3 is not finished, but a little bit of this acid is left in the solution. Therefore, when sodium bicarbonate is added to the solution with citric acid, sodium citrate salt (C6H5O7Na3) and carbonic acid (H2CO3) are formed, which is rapidly broken down into water (H2O) and carbonic oxide (CO2).

C6H8O7 + NaHCO3 ⇒ C6H5O7Na3 + 3 H2CO3

C6H5O7Na3 + 3 H2CO3 ⇔ C6H5O7Na3 + 3 H2O + 3 CO2

5 0
2 years ago
Suppose you need 7.0 m of Grade 70 tow chain, which has a diameter of 38" and weighs , 2.16/kgm to tow a car. How would you calc
STatiana [176]

Answer : The mass of 7.0 m chain is, 15.12 kg

Explanation :

As we are given that,

The weight of the chain per unit length = 2.16 kg/m

Now we have to determine the mass of chain for 7.0 m length.

As, the mass of 1 m length of chain = 2.16 kg

So, the mass of 7.0 m length of chain = \frac{7.0m}{1m}\times 2.16kg

                                                                = 15.12 kg

Therefore, the mass of 7.0 m chain is, 15.12 kg

3 0
2 years ago
To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is diluted to 0.500 L. Analysis of the dilute
julia-pushkina [17]

Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molar concentration of undiluted cognac = ?

M_2 = molar concentration of diluted cognac = 0.0844 M

V_1 =  volume of undiluted cognac = 5.00 mL = 0.005 L

V_2 = volume of diluted cognac = 0.500 L

Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.

M_1\times 0.005L=0.0844M\times 0.500L

M_1=8.44M

Therefore, the molar concentration of ethanol in the undiluted cognac is 8.44 M

4 0
2 years ago
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