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Damm [24]
2 years ago
11

A large clump of ice is placed into a saucepan and heated to at least 1000C. Explain the changes that would take place by using

the following terms: physical change, states of matter, compound, solid, liquid, vapor and temperature change."
Chemistry
2 answers:
Mamont248 [21]2 years ago
7 0
By start heating the water so,
1- the physical changes to the water will begin by going through different states of matter such as solid, liquid and gas vapor. 

2- Water is a compound, not an element (H2o).

3- It will change according to the temperature change also:

a- At zero C° it is at a freezing temperature.

b- when it starts to be heated from 0C° to 100 c°, it starts to change from freezing to the liquid state. 

c- At 100C° the water starts to change from liquid to vapor state until it disappears. 

IgorLugansk [536]2 years ago
7 0

Explanation:

When a large clump of ice is heated in a sauce pan at about 1000 degree celsius then the ice will start to melt. As a result, the solid state of water which is ice will change into liquid state.

And when the liquid starts to boil as temperature reaches 100 degree celsius then liquid state will change into vapor state until it disappears.

Since there is only change in state so, it is a physical change. Thus, states of matter will change when there will be change in temperature.

Hence, state of compound H_{2}O will change along with change in temperature.

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An alien civilization has different names and symbols for six elements. Place each element in the correct location in the period
Margarita [4]

Answer:

why whould I know that!!??

Explanation:

3 0
1 year ago
Read 2 more answers
7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa?
suter [353]
<h3>Answer:</h3>

              0.8133 mol

<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

                 n  =  0.8133 mol

4 0
2 years ago
Read 2 more answers
If element x forms the oxides xo and x2o3 the oxidation numbers of element x are
Deffense [45]

Answer:

b) +2 and +3.

Explanation:

Hello,

In this case, given the molecular formulas:

XO

And:

X_2O_3

We can relate the subscripts with the oxidation states by knowing that they are crossed when the compound is formed, for that reason, we notice that oxygen oxidation state should be -2 for both cases and the oxidation state of X in the first formula must be +2 since both X and O has one as their subscript as they were simplified:

X^{+2}O^{-2}

Moreover, for the second case the oxidation state of X should be +3 in order to obtain 3 as the subscript of oxygen:

X_2^{+3}O_3^{-2}

Thus, answer is b)+2 and +3

Best regards.

3 0
1 year ago
it takes 513 kj to remove a mole of electrons from the atoms at the surface of a piece of metal. how much energy does it take to
schepotkina [342]

Answer:

The right solution is "8.5\times 10^{-19} \ joule".

Explanation:

As we know,

1 mole electron = 6.023\times 10^{23} \ no. \ of \ electrons

Total energy = 513 \ KJ

                     = 513\times 1000 \ joule

For single electron,

The amount of energy will be:

= \frac{513\times 1000}{(6.023\times 10^{23})}

= 8.5\times 10^{-19} \ joule

8 0
2 years ago
How many significant figures the measurement have 56.0g 0.0004m 1003ml 0.0350s
Setler [38]
In order to do this, we have to first know the significant figure rules.
<span>Rule #1: All non-zero digits are significant. (1234)
 Rule #2: Zeros in front of a number are not significant. (0.093)
 Rule #3: Zeros between non-zero digits are significant. (78309)
 Rule #4: Zeros at the end of a number are significant if there is a decimal point in the number. (0.05470)

So by going by the rules, 56.0g has three sig figs, because there is a decimal point.
0.0004m only has one sig fig, according to Rule #2.
1003ml has 4 sig figs, because the zeroes are wedged in the two sig fig numbers.
And lastly, 0.0350s has 3 sig figs because the number after a decimal point counts.

</span>
7 0
1 year ago
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