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AlladinOne [14]
2 years ago
14

Hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. He spent a total of $47.65. If Hugh bought

3 magazines, how many books did he buy?
The equation that models the problem is 3.95m + 8.95b = 47.65, where m is the number of magazines and b is the number of books.
Mathematics
1 answer:
Hoochie [10]2 years ago
8 0

Answer:

4 books.

Step-by-step explanation:

We have been that Hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. He spent a total of $47.65.

The equation 3.95m+8.95b=47.85 represents the given problem.

To find the number of books, b, bought by Hugh, we will substitute m=3 in our given equation.

3.95(3)+8.95b=47.65

11.85+8.95b=47.65

11.85-11.85+8.95b=47.65-11.85

8.95b=35.8

\frac{8.95b}{8.95}=\frac{35.8}{8.95}

b=4

Therefore, Hugh can buy 4 books.

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