Answer:
STEP 1: Find the circumference:
Circumference = 2πr
Circumference = 2π(14) = 28π cm
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STEP 2: Find the length of the arc:
Length of the arc = 36/360 x 28π
Length of the arc = 8.8 cm
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Answer: The length of the arc is 8.8 cm
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hope it helpssss
Mark it as brilliant answer plzzz
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Step-by-step explanation:
The simplest method is "brute force". Calculate each term and add them up.
∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)
∑ = 3 + 6 + 9 + 12 + 15
∑ = 45
∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²
∑ = 4 + 16 + 36 + 64
∑ = 120
∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)
∑ = -4 + -2 + 0 + 2
∑ = -4
4. 1 + 1/4 + 1/16 + 1/64 + 1/256
This is a geometric sequence where the first term is 1 and the common ratio is 1/4. The nth term is:
a = 1 (1/4)ⁿ⁻¹
So the series is:
5. -5 + -1 + 3 + 7 + 11
This is an arithmetic sequence where the first term is -5 and the common difference is 4. The nth term is:
a = -5 + 4(n−1)
a = -5 + 4n − 4
a = 4n − 9
So the series is:
Answer:
A, (1, 3+1/2)
Step-by-step explanation:
Midpoint formula for reference: m= {(x1 + x2)/2, (y1 + y2)/2}
Plugging in the points we get: m= {(8 - 6)/2, (5 + 2)/2}
Now we simplify using PEMDAS. First step is parentheses.
m= {2/2, 7/2}
Simplifying again (and making 7/2 a mixed number), it becomes
m= {1, 3+1/2}
Hope this helps!
You didn't say if the car bought is the new car or the old car so I'm assuming the car bought for $22,500 is the new car.
You divide 22,500 by 2 to get the cost of the old car. When you do this, you find out the old car costed $11,250.
the equation is 22,500/2=p
If $22,500 is the cost of the old car, then it's not my fault that the poster did not make it clear. If the previous car costed $22,500, then the previous car costed $22,500
What you put is correct. A’B’C’D’ is what would be shown if you rotate ABCD 90 degrees clockwise
