Answer:
An alternative definition for the acceleration ax that can be written in terms of 
and 
is 
Step-by-step explanation:
We know that :
Now we are supposed to find an alternative definition for the acceleration ax that can be written in terms of and
So, We will use chain rule over here :
![a_x=\frac{dv_x}{dt}\\a_x=\frac{dv_x}{dt} \times \frac{dx}{dx}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt} [\frac{dx}{dt}=v_x]\\a_x=\frac{dv_x}{dx} \times v_x\\a_x=v_x\frac{dv_x}{dx}](https://tex.z-dn.net/?f=a_x%3D%5Cfrac%7Bdv_x%7D%7Bdt%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdt%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdx%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdt%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%20%5B%5Cfrac%7Bdx%7D%7Bdt%7D%3Dv_x%5D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20v_x%5C%5Ca_x%3Dv_x%5Cfrac%7Bdv_x%7D%7Bdx%7D)
Hence an alternative definition for the acceleration ax that can be written in terms of and is
The arrow is fired with an initial upward velocity of 32ft/s
Substitute t = 0, to get the initial height
Hey!
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Let's Solve A:
1/2 = 0.5
0.5 + 0.30 = 0.80
a = 0.80
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Let's Solve B:
3/4 = 0.75
0.10 + 0.75 = 0.85
b = 0.85
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Let's Solve C:
1/3 ≈ 0.33
0.33 + 0.50 = 0.83
c = 0.83
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Let's Solve D:
1/3 ≈ 0.33
0.33 + 0.40 = 0.73
d = 0.73
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Answer:
By solving each equation we can see that option A has the lowest value!
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Hope This Helped! Good Luck!
