Question

As a 15.1-gram sample of a metal absorbs 48.75 J of heat, its temperature increases 25.0 K. What is the specific heat capacity of the metal? (1) 0.129 J/g•K (2) 1.95 J/g•K (3) 3.23 J/g•K (4) 7.74 J/g•K

Answer 1

The formula for the specific heat capacity can be expressed as:

$c = \frac{Q}{m*T}$

Here,
c = Specific Heat Capacity
Q = Energy absorbed = 48.75 J
m = Mass of the substance = 15.1 gram 
T = Change in temperature = 25 K

Using the values in above formula, we get:

$c = \frac{48.75}{15.1 * 25} = 0.129 J/g.K$

So the first option 0.129 J/g.K is the correct answer.