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faltersainse [42]
2 years ago
9

The system of equations is graphed on the coordinate plane. y=−12x−1y=14x−4 A graph with a blue line passing through coordinates

(0, -4) and (4, -3) and a red line passing through coordinates (0, -1) and (4, -3). Enter the coordinates of the solution to the system of equations in the boxes. ( , ​ )

Mathematics
1 answer:
Anika [276]2 years ago
8 0
We have that

 case 1)
<span>system of equations is
</span><span>y=−12x−1
y=14x−4

using a graph tool
see the attached figure

the solution of the system  is the point (0.115,-2.385)

case 2)
</span>system of equations is
<span>blue line passing through coordinates A (0, -4) and B (4, -3)
</span><span>red line passing through coordinates   C(0, -1) and  D (4, -3)

</span>using a graph tool
see the attached figure

the solution of the system  is the point (4,-3)<span>

</span>

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This is how we solved and make the equation.
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2 years ago
One catcher's mitt and 10 outfielder's gloves cost $239.50. How much does each item cost if 1 catcher's mitt and 5 outfielder's gl
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Make an equation for each statement with x being catcher's mitts and y being outfielder's gloves.

x + 10y = 239.50       and        x + 5y = 134.50

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What is the following product? (StartRoot 12 EndRoot + StartRoot 6 EndRoot) (StartRoot 6 EndRoot minus StartRoot 10 EndRoot)
Crank

Answer:

The product results in: 6\,\sqrt{2} -2\,\sqrt{30} +6-2\,\sqrt{15}, which agrees with answer A of the given choices.

Step-by-step explanation:

We need to apply distributive property for the product of two expressions each consisting of two terms, and also use the properties of products of radicals of the same root:

(\sqrt{12} +\sqrt{6} )(\sqrt{6} -\sqrt{10} )=\\=\sqrt{12*6} -\sqrt{12*10} +\sqrt{6*6} -\sqrt{6*10} =\\=\sqrt{72} -\sqrt{120} +\sqrt{36} -\sqrt{60}

and now, we extract as many factors we can from the roots to reduce them:

\sqrt{72} -\sqrt{120} +\sqrt{36} -\sqrt{60} =\\=6\,\sqrt{2} -2\,\sqrt{30} +6-2\,\sqrt{15}

5 0
2 years ago
Read 2 more answers
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