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tigry1 [53]
2 years ago
8

Tickets to a basketball game can be ordered online for a set price per ticket plus a $5.50 service fee. The total cost in dollar

s for ordering 5 tickets is $108.00. Which linear function represents c, the total cost, when x tickets are ordered?
Mathematics
2 answers:
adelina 88 [10]2 years ago
6 0
Cost=flatfee+changingfee
flatfee=5.50
changingfee=costperticket times number of tickets

we know that 5 times cost per ticket=108
divide by 5
cost per ticket=21.6
c=number of tickets

totalcost=5.5+21.6c
TC=21.6c+5.5
erica [24]2 years ago
5 0

Let

c--------> the total cost

x------> the number of tickets

z------> the cost of one ticket without service fee

we know that

108=5.50+5z

solve for z

combine like terms

5z=108-5.50

5z=102.50

z=\$20.50

The linear function is equal to

c=5.50+20.50x

therefore

<u>the answer is</u>

c=5.50+20.50x

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General solution of equation sin x + sin 5x = sin 2x + sin 4x is
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7 0
2 years ago
Consider the polynomial: StartFraction x Over 4 EndFraction – 2x5 + StartFraction x cubed Over 2 EndFraction + 1 Which polynomia
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Answer:

- 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

Step-by-step explanation:

Given

\frac{x}{4} - 2x^5 + \frac{x^3}{2} + 1

Required

The standard form of the polynomial

The general form of a polynomial is

ax^n + bx^{n-1} + cx^{n-2} +........+ k

Where k is a constant and the terms are arranged from biggest to smallest exponents

We start by rearranging the given polynomial

- 2x^5+ \frac{x^3}{2} +\frac{x}{4}  + 1

Given that the highest exponent of x is 5;

Let n = 5

Then we fix in the missing terms in terms of n

- 2x^5+ 0x^{n-1} +  \frac{x^3}{2} +0x^{n-3}+\frac{x}{4}  + 1

Substitute 5 for n

- 2x^5+ 0x^{5-1} +  \frac{x^3}{2} +0x^{5-3}+\frac{x}{4}  + 1

- 2x^5+ 0x^{4} +  \frac{x^3}{2} +0x^{2}+\frac{x}{4}  + 1

Hence, the standard form of the given polynomial is - 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

3 0
2 years ago
Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.
s344n2d4d5 [400]

Answer:

The width of lot B is 11 feet, so option A is correct.

Step-by-step explanation:

Given:

  • Two rectangular properties share a common side.  
  • Lot A is 33 feet wide and 42 feet long.  
  • The combined area of the lots = 1,848 square feet.  

To find:

How many feet wide is Lot B?  

Solution:

we know that, area of a rectangle is length x breadth

Then area of lot A = 33 x 42 = 1386 square feet.

And area of lot B = width x 42

Now, we are given that, total area = 1848  

area of lot A + area of lot B = 1848  

1386 + width x 42 = 1848  

width x 42 = 1848 – 1386  

width x 42 = 462  

width =\frac{42}{462}

width = 11

Hence, the width of lot B is 11 feet, so option A is correct.

7 0
2 years ago
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