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Luda [366]
2 years ago
12

The recipe makes enough stew for 6 people, and the ingredients cost $9.75. How much would it cost to serve 24 people? Use the ra

te table to solve the proportion.
Mathematics
3 answers:
maxonik [38]2 years ago
6 0
Well, you have to multiply the 6 by 4 and the 9.75 by 4 because there are going to be 24 people. 6 • 4 is 24 and 9.75 • 4 = 39!
Phantasy [73]2 years ago
6 0

Answer: The required cost of ingredients that would serve the recipe to 24 people is $39.

Step-by-step explanation:  Given that a recipe makes enough stew for 6 people and the ingredients cost $9.75.

We are to find the cost of the ingredients that would make recipe to serve 24 people.

We are to use the rate table to solve the given problem.

Since the rate of increase of number of people is given by

\dfrac{24}{6}=4.

Therefore, we will multiply the cost of ingredients for 6 people by 4.

Therefore, the cost of ingredient that makes the recipe to serve 24 people will be

=9.75\times 4\\\\=39.

Thus, the required cost of ingredients that would serve the recipe to 24 people is $39.

Guest1 year ago
0 0

In the second ratio, the number of people is the denominator. It should be the numerator to match the first ratio.

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the daily production cost, c, for x units is modeled by the equation: c = 200 – 7x 0.345x2 explain how to find the domain and ra
jenyasd209 [6]
C(x) = 200 - 7x + 0.345x^2

Domain is the set of x-values (i.e. units produced) that are feasible. This is all the positive integer values + 0, in case that you only consider that can produce whole units.

Range is the set of possible results for c(x), i.e. possible costs.

You can derive this from the fact that c(x) is a parabole and you can draw it, for which you can find the vertex of the parabola, the roots, the y-intercept, the shape (it open upwards given that the cofficient of x^2 is positive). Also limit the costs to be positive.

You can substitute some values for x to help you, for example:

x      y
0    200
1    200 -7 +0.345 = 193.345
2    200 - 14 + .345 (4) = 187.38
3    200 - 21 + .345(9) = 182.105
4    200 - 28 + .345(16) = 177.52
5    200 - 35 + 0.345(25) = 173.625
6    200 - 42 + 0.345(36) = 170.42

10  200 - 70 + 0.345(100) =164.5
11 200 - 77 + 0.345(121) = 164.745
 
 
The functions does not have real roots, then the costs never decrease to 0.

The function starts at c(x) = 200, decreases until the vertex, (x =10, c=164.5) and starts to increase.

Then the range goes to 164.5 to infinity, limited to the solutcion for x = positive integers.

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2 years ago
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Samantha wants to use her savings of $1150 to buy shirts and watches for her family. The total price of the shirts she bought wa
irakobra [83]
The cost of the shirts is stable, so we can subtract $1150 - $84, which = $1066. Now we want to find how many watches we can buy with $1066, or how many times $99 fits into $1066. So divide 1066 by 99 to get 10.77. You can't buy 77ths of a watch, so round it down to 10 and you have your answer. Samantha can buy 10 watches.
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Which step shows the result of applying the subtraction property of equality?
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The answer is  step 2
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1 year ago
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Quadrilateral ABCD is inscribed in circle P as shown. Which statement is necessarily true? A. `"m"/_A +"m"/_B = "m"/_C + "m"/_D
pogonyaev

Opposite angles of an inscribed quadrilateral are supplementary, so it is true that ...

... B. m∠A + m∠C = m∠B + m∠D . . . . . = 180°

3 0
1 year ago
Determine whether the lines are parallel, intersect, or coincide. x-5y=0, y+1=1/5(x+5)
MAXImum [283]

<u>Answer-</u>

<em>The lines are two </em><em>coinciding lines</em><em> or the </em><em>same lines</em><em>.</em>

<u>Solution-</u>

The given line equations are

the first one,

\Rightarrow x-5y=0  

the second one,

\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0

As we know two line equations A_1x+B_1y+C_1=0 and A_2x+B_2y+C_2=0 will be,

  1. Parallel if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}
  2. Coincide if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}
  3. Intersect if, \dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}

As here,

\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}

\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

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