As per given conditions there are two directions along which forces are acting
1. Net force along left direction is given as
2. Net force towards right direction is given as
now since the two forces here in opposite direction so here we will have net force given as
so here net forces must be 440 N towards right
The force applied by the man is 60 N
Explanation:
We can solve this problem by applying Newton's second law, which states that:
(1)
where
is the net force acting on the child+cart
m is the mass of the child+cart system
a is their acceleration
In this problem, we have:
m = 30.0 kg is the mass
And there are two forces acting on the child+cart system:
Therefore we can write the net force as
where R is negative since its direction is opposite to the motion
So eq.(1) can be rewritten as
And solving for F,
Learn more about Newton's second law:
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Answer with Explanation:
We are given that
Charge on proton,q=
a.We have to find the electric potential of the proton at the position of the electron.
We know that the electric potential
Where
B.Potential energy of electron,U=
Where
Charge on electron
=Charge on proton
Using the formula