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2 years ago

If Mary deposits $275 in principal at an interest rate of 3.2 percent,how much interest will she earn in one year

Mathematics

1 answer:

Free_Kalibri [48]2 years ago

3 0

0.032*$275 = $8.80 . . . . interest on Mary's account for the year.

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Triangles ΔABC ≅ ΔBAD so that C and D lie in the opposite semi-planes of segment AB. Prove that segment CD bisects segment AD.

kolbaska11 [484]

Answer:

See explanation

Step-by-step explanation:

Triangles ΔABC and ΔBAD are congruent. So,

AB ≅ BA;
AC ≅ BD;
BC ≅ AD;
∠ABC ≅ ∠BAD;
∠BCA ≅ ∠ADB;
∠CAB ≅ ∠DBA.

Consider triangles AEC and BED. In these triangles,

AC ≅ BD;
∠EAC ≅ ∠EBD (because ∠CBA ≅ ∠BAD);
∠AEC ≅ ∠BED (as vertical angles).

So, ΔAEC ≅ ΔBED. Thus,

AE ≅ EB.

This means that segment CD bisects segment AD.

6 0

2 years ago

(30 points) The coordinates of the vertices of quadrilateral JKLM are J(−3, 2) , K(3, 5) , L(9, −1) , and M(2, −3) .

Tpy6a [65]

(30 points) The coordinates of the vertices of quadrilateral JKLM are J(−3, 2) , K(3, 5) , L(9, −1) , and M(2, −3) .
Which statement correctly describes whether quadrilateral JKLM is a rhombus?

Quadrilateral JKLM is not a rhombus because there is only one pair of opposite sides that are parallel.

6 0

2 years ago

Read 2 more answers

Dimensional analysis: 1.35 kilometers per second= ? miles per hour

Elza [17]

Answer:

Hey there!

1.35 km/s would equal 3020 miles per hour.

Let me know if this helps :)

4 0

1 year ago

Read 2 more answers

A composite figure is comprised of a square, trapezoid, and a rectangle. The square has side lengths of 10 centimeters. The trap

Evgesh-ka [11]

The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

Step-by-step explanation:

The given is,

Dimensions of square has length of 10 cm

Trapezoid has base lengths of 8 cm and 14 cm

The length of the trapezoid is 4 cm

Rectangle has side length of 20 cm and 6 cm

Step:1

Area of composite figure = Area of square + Area of Trapezoid

+ Area of rectangle.......................(1)

Step:2

Formula for area of square,

$A_{square} = a^{2}$

where, a - side of length = 10 cm

$=10^{2}$

$=100$

Area of square, $A_{square}$ = 100 Square centimeter

Step:3

Formula for area of Trapezoid,

$A_{Trapezoid}$ = $\frac{a+b}{2} h$ .......................................(2)

Where, a - 8 cm

b - 14 cm

h - 4 cm

From equation (2)

= $\frac{8+14}{2} 4$

= $(11)(4)$

= 44

Area of Trapezoid, $A_{Trapezoid}$ = 44 square centimeters

Step:4

Formula for area of rectangle,

$A_{Rectangle} =lb$ ......................................(3)

Where, l = 20 cm

b = 6 cm

Equation (3) becomes,

$= (20)(6)$

= 120

Area of rectangle, $A_{Rectangle}$ = 120 square centimeters

Step:5

From Equation (1),

$A_{Composite}$ = 100 + 44 + 120

= 264 square centimeters

Result:

The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

4 0

2 years ago

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In quadrilateral RSTU, RS = 60 mm, ST = 60 mm, TU = 112 mm, and UR = 112 mm.

lesya692 [45]

Answer:

A. factor 4

Step-by-step explanation:

Just choose any side of the original one e.g 60mm and divide it by the lenght of the same side of the new one. In A. this gives you 60mm/15mm = 4. Then you can multiply the other lengths with that factor and if the result is equal to the sides of your original one you found the solution.

5 0

2 years ago