There are no given figures. I'll just show what the difference is. Let us assume the following Principal = 10,000 interest rate = 12% term = 4 years
Simple Interest = Principal * interest rate * term S.I = 10,000 * 12% * 4 years S.I = 4,800
Total value at the end of 4 yrs = 10,000 + 4,800 = 14,800
Compounded Interest. Compounded quarterly. A = P(1 + r/n)^n*t A = 10,000 (1 + 12%/4)^4*4 A = 10,000 (1.03)^16 A = 10,000 (1.60) A = 16,000 value after 4 years.
Part B: Equation of the line in point-slope form is y - 1350 = -75×(x - 2) Equation of the line in slope-intercept form is y = -75·x + 1500
Equation of the line in standard form is y + 75·x = 1500
Part C:
f(x) = -75·x + 1500
Part D: $1,125 Step-by-step explanation: The information given are; x, g(x) 0, $1,500 2, $1,350 4, $1,200 The equation of a straight line relation between the x, and y, coordinates in slope and intercept form is y = m·x + c Where; m = The slope c = The y-intercept From the data, we have two points, (x₁, y₁), (x₂, y₂) given as (0, 1,500), (2, 1350); The y-intercept = y at x = 0 = 1,500 y = -75·x + 1500 x = 1500/75 = 20
Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/5966450-the-table-of-values-represents-a-linear-function-g-x-where-x-is.html
