The graph of the logarithmic function f(x) = loga(x) passes through the points and . The graph lies the y-axis.
2 answers:
The question is incomplete. But this explanation will help you very much.
1) Regarding the function
, its graph always passes through the points (1,0) and (a,1).
That is due to the properties of logarithm function:
a)
b)
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That in turn is due to the properties of the exponential functions.
a^0 = 1 and a^1 = a
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2) Regarding the y-axis.
The function will never touch the y-axis, because the logaritm of zero is not defined. So the graph lies to the righ of the y-axis (i.e. the domain of the function is x > 0)
1) Regarding the function
That is due to the properties of logarithm function:
a)
b)
<span>
That in turn is due to the properties of the exponential functions.
a^0 = 1 and a^1 = a
</span>
2) Regarding the y-axis.
The function
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Answer:
The equations that represent the reflected function are
Step-by-step explanation:
The correct question in the attached figure
we have the function
we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore
The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)
An equivalent form will be
therefore
The equations that represent the reflected function are
