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2 years ago

The graph of the logarithmic function f(x) = loga(x) passes through the points and . The graph lies the y-axis.

2 answers:

8 0

The question is incomplete. But this explanation will help you very much.

1) Regarding the function $log_ax$ , its graph always passes through the points (1,0) and (a,1).

That is due to the properties of logarithm function:

a) $log_a1=0$

b) $log_aa=1$

That in turn is due to the properties of the exponential functions.

a^0 = 1 and a^1 = a

2) Regarding the y-axis.

The function $log_ax$ will never touch the y-axis, because the logaritm of zero is not defined. So the graph lies to the righ of the y-axis (i.e. the domain of the function is x > 0)

lesya692 [45]2 years ago

3 0

Answer:

(1, 0)

Step-by-step explanation:

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Solve for r. 4×r=1/2 Write your answer as a fraction or as a whole or mixed number

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Answer:

V=4xr

Step-by-step explanation:

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2 years ago

If you have a whale that weighs 5000lb and he eats 150lb a day. How do you figure out what percent of his body weight he require

Alina [70]

Answer:

Step-by-step explanation:

To find how much of his body weight in food he requires daily, divide:

$\frac{150}{5000}\div\frac{50}{50}=\frac{3}{100}=0.03=3\%$

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2 years ago

The table below shows the amount of lemon juice and sugar needed to make three different-sized batches of lemonade using the sam

mash [69]

Answer:

j = 2.5s

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Lemon juice (mL) Sugar (gr)

Batch A 500 200

Batch B 750 300

Batch C 1,500 600

2. Write an equation to describe the relationship between j, the amount of lemon juice in mL, and s, the amount of sugar in g.

Ratio = Amount of lemon juice/Amount of sugar

Ratio = 500/200 = 750/300 = 1,500/600

Ratio = 2.5

Now, we can write the equation, this way:

j = 2.5s

8 0

2 years ago

Read 2 more answers

Jun and deron are applying for summer jobs at a local restaurant. after interviewing them, the restaurant owner says, "the proba

mr Goodwill [35]

As restaurant owner The probability of hiring Jun is 0.7 => p(J) The probability of hiring Deron is 0.4 => p(D) The probability of hiring at least one of you is 0.9 => p(J or D) We have a probability equation: p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D) p(J and D) = 1.1 - 0.9 = 0.2 So the probability that both Jun and Deron get hired is 0.2.

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2 years ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0

2 years ago