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Eduardwww [97]
2 years ago
10

Gerry and his family have moved into a new home with a great backyard. In the yard, they plan to have a garden, a lawn, and a pa

tio. The diagram shows the actual dimensions of the backyard.
Chemistry
2 answers:
Grace [21]2 years ago
8 0

Answer:

Base=30 cm

Height=12 cm

Length=24 cm

Width=12 cm

Anestetic [448]2 years ago
5 0
The base of the garden in the scale drawing is 30 centimeters. (because 10x3 equals to 30)
The height of the garden in the scale drawing is 12 centimeters. (because 4x3 equals to 12)
The length of the patio in the scale drawing is 24  centimeters. (because 8x3 equals to 24)
The width of the patio in the scale drawing is 12 centimeters. (because 4x3 equals to 12)
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Describe two shortcomings of the pennium model for isotopes
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let me know when u find out plz because i would like to know as well its one of my chemistry qustions in an assiment. :)

3 0
2 years ago
Which statement is true of a reversible reaction at equilibrium?
Vedmedyk [2.9K]

Answer:

D.

The concentration of reactants and the concentration of products are constant.

Explanation:

pls mark as brainliest

7 0
2 years ago
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Combustion of gasoline in automobiles produces poisonous gases. Catalytic converters that contain solid platinum, palladium, and
bagirrra123 [75]
It provides an alternative pathway for the rxn.
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2 years ago
Be sure to answer all parts. Consider the following reaction: Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s) E o (Fe2+ / Fe) = −0.4400 V, E
Bezzdna [24]

Answer:

EMF = -0.17 V

No

Explanation:  

For the reaction :

Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s)

we will be using the Nersnt equation to calculate Ecell:

Ecell =  Eº -0.0592 V/2 ln Q

where Q = ( Fe⁺² )/ (Cd²⁺)

and (Fe²⁺) and (Cd²) are the molar concentration of Fe²⁺ and Cd²⁺

Reduction

Fe²⁺ + 2e⁻  ⇒ Fe(s)      Eº red = -0.4400 V

Oxidation

Cd (s)   ⇒ Cd²⁺ + 2e⁻    Eº ox = +0.4000 V

Eºcell = Eox + Ered = 0.4000 V + (-0.4400 V) = -0. 0400 V

Ecell = Eº -0.0692 V/2 ln Q = -0.0400 V - 0.0592/2 ln ( 0.80/0.010 ) = -0.17V

No because Eºcell is negative and  ΔºG will be positive since

                               ΔºG  =  -nFEºcell

5 0
2 years ago
A mixture of KCl and KNO3
Tems11 [23]
Answer is: <span>The percent of KCl in the mixture is closest to </span><span>a) 40%.
</span>
If we use 100 grams of mixture:
ω(K) = 44.20% ÷ 100% = 0.442.
m(K) = 0.442 · 100 g = 44.2 g.
n(K) = 44.2 g ÷ 39.1 g/mol.
n(K) = 1.13 mol.
n(KCl) + n(KNO₃) = n(K)
m(KCl) = x.
m(KNO₃) = y.
Two equtions:
1) x + y = 100 g.
2) m(KCl)/M(KCl) + m(KNO₃)/M(KNO₃) = 1.13 mol.
x/74.55 g/mol + y/101.1 g/mol = 1.13 mol.
From first equation find x = 100 - y and put in second equation:
(100 - y)/74.55 + y/101.1 = 1.13 /×101.1.
135.61 - 1.356y + y = 114.24.
0.356y = 22.37 g.
y = 62.83 g.
x = m(KCl) = 100 g - 62.83 g = 37.17 g.
8 0
2 years ago
Read 2 more answers
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