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Lunna [17]
2 years ago
7

Susie is thinking about changing her auto insurance policy at Fret-No-More Auto Insurance. Her current policy includes the follo

wing options: $50/100,000 limit for bodily injury, $25,000 limit for property damage, $250 deductible for collision, and $50 deductible for comprehensive. Which of the following changes would increase Susie’s limits the most without increasing her monthly premium by more than $5.00?
Mathematics
2 answers:
Katen [24]2 years ago
8 0

Answer:

C. Increase coverage on bodily injury to $100/300,000 and on property damage to $50,000

Step-by-step explanation:

elena55 [62]2 years ago
5 0
From her current policy which includes the $50/100,000 limit for bodily injury, $25,000 limit for property change, $250 deductible for collision, and $50 deductible for comprehensive. To increase Susie’s limits the most without increasing her monthly premium by more than $5.00 she should: 

Increase coverage on bodily injury to $100/300,000 and on property damage to $50,000.


<span>I hope this helps, Regards.</span>
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Use forward and backward difference approximations of O(h) and a centered difference approximation of O(h2) to estimate the firs
strojnjashka [21]

Answer:

Answer has explained below.

Step-by-step explanation:

Consider the function is:

F(x) = 25x3 – 6x2 +7x -88

Differentiate with respect to x, we get

F’(x) = 25. 3x2 – 6.2x + 7

       = 75x2 – 12x +7

At x = 2, we have

F (2) = 25(2)3 – 6(2)2 + 7(2)-88

        =102

And f’(2) = 75(2)2 – 12 (2) +7

               =283

Now, calculate forward divided difference as:

xi + 1 = xi + h

        =2 + 0.25

        =2.25

F (xi + 1) = f (2.25) = 25 (2.25)3 – 6(2.25)2 +7(2.25) -88

                            =182.21

f’(2) = f(2.25) – f(2) / 0.25 = 182.21 – 102 / 0.25

                                             = 320.84

Єt = 283 – 320.8 / 283 = -13.36%

Now calculate backward divided difference:

Xi-1 = xi –h = 2 – 0.25 = 1.75

F(xi-1)= f(1.8) = 25 . (1.8)3 -6 (1.8)2 + 7 (1.8) – 88

                       = 50.96

F’(2) = f(2) – f(1.8) / 0.25 = 102 – 50.96 / 0.25 = 204.16

Єt = 283 – 204.16 / 283 = 27.86%

Finally, centered divided difference is obtain by inserting f(xi+1) and f (xi-1):

F’(2) = f(2.25) – f(1.8) /2 x 0.25 = 320.84 -50.96 / 0.5 = 539.68

Єt = 283 – 539.68 / 283 = -90.7%

6 0
2 years ago
Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?
REY [17]
<span>Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?


–5</span>
5 0
2 years ago
Read 2 more answers
Which congruence theorem can be used to prove △MLQ ≅ △NPQ?<br><br> AAS <br> SSS <br> ASA <br> SAS
storchak [24]
Answer: SSS

Proof:
In ΔMLQ and ΔNPQ,
MQ = NQ (given) S
Since Q is the midpoint of LP, by definition, LQ = QP (S)
LM = PN (given) S

∴ ΔMLQ ≡ ΔNPQ (SSS)
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Anna set up a lemonade stand on her block over the summer. She recorded each day’s high temperature and the number of cups of le
Alexxx [7]

Answer:

Residual = -2

The negative residual value indicates that the data point lies below the regression line.

Step-by-step explanation:

We are given a linear regression model that relates daily high temperature, in degrees Fahrenheit and number of lemonade cups sold.

y = -34+ \frac{3}{5}  x

Where y is the number of cups sold and x is the daily temperature in Fahrenheit.

Residual value:

A residual value basically shows the position of a data point with respect to the regression line.

A residual value of 0 is desired which means that the regression line best fits the data.

The Residual value is calculated by

Residual = Observed value - Predicted value

The predicted value of number of lemonade cups is obtained as

y = -34+ \frac{3}{5} (95)\\\\y = -34+ 3 (19)\\\\y = -34+ 57\\\\y = 23

So the predicted value of number of lemonade cups is 23 and the observed value is 21 so the residual value is

Residual = Observed value - Predicted value

Residual = 21 - 23

Residual = -2

The negative residual value indicates that the data point lies below the regression line.

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2 years ago
The developer of a new plant fertilizer gathered data about the quantity of fertilizer applied to a lemon tree and the number of
saw5 [17]

Answer:

Yes, because the slope of the line is closer to 0 than to 1, which indicates a strong association between the variables.

Step-by-step explanation:

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