All categories

2 years ago

Why does an excise tax on gasoline exist? Check all that apply.

Business

1 answer:

nevsk [136]2 years ago

6 0

Answer:

C) To discourage travel by automobile by making gasoline more expensive

D) To fund highway repairs and other special projects

Explanation:

Excise taxes are frequently levied upon cigarettes, liquor, fuel, and betting. These are regularly viewed as pointless or superfluous merchandise and ventures. To raise imposes on them is to increase their costs and to lessen the sum they are utilized. In this unique situation, extract duties are occasionally known as "transgression charges".

Excise taxes are basically for organizations. Consumers might see the expense of extract imposes straightforwardly. Shippers, who, at that point, pass the assessment on to buyers through higher costs, pay many extract charges.

You might be interested in

Question 6 of 10

Fiesta28 [93]

Answer: A

Explanation: Apex

5 0

2 years ago

A company purchased a tract of land for its natural resources at a cost of $1,500,000. It expects to mine 2,000,000 tons of ore

Natasha2012 [34]

Answer:

Option c is the correct answer.

Explanation:

The depletion expense or charge for the period can be calculated using the following formula,

Depletion expense = [(Cost - Salvage Value) / Total units expected to be mined] * Units mined during the period

Depletion expense = [(1500000 - 250000) / 2000000] * 150000

Depletion expense = $93750

The entry to record the expense is,

Depletion expense 93750 Dr

Accumulated depletion 93750 Cr

So, option c is the correct answer.

7 0

2 years ago

We are evaluating a project that costs $735,200, has an eight-year life, and has no salvage value. Assume that depreciation is s

Feliz [49]

Answer:

Was your question removed?

Explanation:

3 0

2 years ago

Depreciation Methods On January 2, 2018, Skyler, Inc. purchased a laser cutting machine to be used in the fabrication of a part

crimeas [40]

Answer:

Instructions are listed below.

Explanation:

Giving the following information:

The machine cost $120,000, and its estimated useful life was four years or 920,000 cuttings, after which it could sell for $5,000.

Each method has a different formula. In the straight-line depreciation, each year's depreciation expense is the same. On the other hand, double-declining balance depreciation expense declines with the years. While the units of production method, depreciation expense varies according to use.

A) Straight-line:

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (120,000 - 5,000)/4= $28,750 per year

B) Double declining balance:

Annual depreciation= 2*[(book value)/estimated life (years)]

Year 1= 2*(115,000/4)= 57,500

Year 2= 2*[(115,000 - 57,500)/4]= 28,750

Year 3= 2*[(57,500 - 28,750)/4]= 14,375

Year 4= 2*[(28,750 - 14,375)/4]= 7,187.5

C) Units of production:

Annual depreciation= [(original cost - salvage value)/useful life of production in units]*units produced

Year 1= [(115,000)/920,000]*200,000= $25,000

Year 2= (0.125)*350,000= 43,750

Year 3= 0.125*260,000= $32,500

Year 4= 0.125*110,000= $13,750

6 0

2 years ago

Burrito King (a new fast-food franchise opening up nationwide) has successfully automated burrito production for its drive-up fa

bezimeni [28]

Answer:

(A)0.6600 (B) 1.325 (C) 0.997 or 1 minute

Explanation:

Solution

Given that:

The constant rate = 30 seconds

The arrival rate according to Poisson distribution is = 45 seconds

Now,

(A) We solve for the average length line of cars

The formula is given below:

Lq = λ²/ 2μ ( μ -λ)

Here,

λ = this is the mean time of arrival rate

μ = This is the mean service rate

Thus we compute for the mean time arrival rate which is given below:

The mean arrival rate λ = arrival rate/ 60 seconds

= 60/45

= 1.33 customer per minute

Then we solve for the means service rate which is given below

The mean service rate μ = 60 seconds/ mean rate

= 60/30 = 2 customer per minute

We will now solve for the average line length in cars which is shown below:

Lq = λ²/ 2μ ( μ -λ)

Lq = 1.33²/2*2 (2-1.33)

Lq = 1.7689/4 (0.67)

Lq = 1.7689/2.68

Lq = 0.6600

Therefore the average length in line for cars is 0.6600 cars

(B) We solve for the average number of cars in the system

Ls =Lq + λ /μ

Ls =0.600 + 1.33/2

Ls =0.6600 + 0.665

Ls = 1.325

Ws = Ls/λ

Ws= 1.325/1.33 = 0.997 or 1.00

The expected time average in the system is 0.997 or 1.00 minutes.

3 0

2 years ago