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inn [45]
2 years ago
3

In the course of the nitrogen cycle, are nitrogen atoms themselves ever created? ever destroyed? 6. are nitrogen atoms ever chan

ged into other kinds of atoms? ever changed into other compounds? explain why or why not.
Chemistry
2 answers:
Fiesta28 [93]2 years ago
8 0
Nitrogen atoms cannot be created nor destroyed or changed into different kinds of atoms because the Law of conversation of matter which states that matter can't be created nor destroyed. But Nitrogen can be changed into different compounds in nitrogen cycle
Law Incorporation [45]2 years ago
8 0

Answer:

In the nitrogen cycle, the atoms of nitrogen are neither destroyed nor created, or changed into other atoms, this process can be illustrated with the help of the law of conservation of matter that states that matter is neither destroyed nor created in any kind of physical or chemical process.  

Nitrogen fixation is a very essential part of the nitrogen cycle, in the process nitrogen in the atmosphere gets transformed to ammonium ions. The formed ammonia then gets transformed into nitrites, and then into nitrates with the help of certain bacteria by the process of nitrification.  

After that, the process of ammonification takes place in which the amino acids and proteins get dissociated to discharge ammonia, generally in the form of the ammonium ion, which is then transformed into nitrogen in order to continue the cycle.  

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 A reaction container holds 5.77 g of P4 and 5.77 g of O2.
Dvinal [7]

Answer:

a) O2 is the limiting reactant

b) 5.75 grams P4O10

c) 5.79 grams P4O6

Explanation:

Step 1: Data given

Mass of P4 = 5.77 grams

Mass of O2 = 5.77 grams

Molar mass of P4 = 123.90 g/mol

Molar mass O2 = 32.0 g/mol

Step 2: The balanced equation

P4 + 3O2 → P4O6

Step 3: Calculate moles of P4

Moles P4 = mass P4 / molar mass P4

Moles P4 = 5.77 grams / 123.90 g/mol

Moles P4 = 0.0466 moles

Step 4: Calculate moles O2

Moles O2 = mass O2 / molar mass O2

Moles O2 = 5.77 grams / 32.0 g/mol

Moles O2 = 0.1803 moles

Step 5: Calculate limiting reactant

P4 is the limiting reactant in this reaction. It will completely be consumed (0.0466 moles). O2 is in excess, there will react 3*0.0466 = 0.1398 moles

There will remain 0.1803 - 0.1398 = 0.0405 moles O2

Step 6: Calculate the amount of P4O6

For 1 mol P4 we'll have 1 mol P4O6

For 0.0466 moles P4 we'll have 0.0466 moles P4O6

Step 7: The balanced equatio

P4O6 + 2O2 → P4O10

We have 0.0466 moles P4O6 and 0.0405 moles O2

Step 8: Calculate the limiting reactant

For 1 mol P4O6 we need 2 moles O2 to produce 1 mol P4O10

O2 is the limiting reactant. It will completely be consumed (0.0405 moles)

P4O6 is in excess. There will react 0.0405/2 = 0.02025 moles

There will remain 0.0466 - 0.02025 = 0.02635 moles P4O6

This is 0.02635 * 219.88 g/mol = 5.79 grams P4O6

Step 9: Calculate moles and mass of P4O10

For 1 mol P4O6 we need 2 moles O2 to produce 1 mol P4O10

For 0.0405 moles O2 we'll have 0.02025 moles P4O10

This is 0.02025 * 283.89 g/mol = 5.75 grams P4O10

3 0
2 years ago
A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5×10−9m, and 1.00 ml
Elis [28]

The concentration of the drug stock solution is 1.5*10^-9 M i.e. 1.5 * 10^-9 moles of the drug per Liter of the solution

Therefore, the number of moles present in 1 ml i.e. 1*10^-3 L of the solution would be =  1 *10^-3 L * 1.5 * 10^-9 moles/1 L = 1.5 * 10^-12 moles

1 mole of the drug will contain 6.023*10^23 drug molecules

Therefore, 1.5*10^-12 moles of the drug will correspond to :

    1.5 * 10^-12 moles * 6.023*10^23 molecules/1 mole = 9.035 * 10^11 molecules

The number of cancer cells = 2.0 * 10^5

Hence the ratio = drug molecules/cancer cells

                          = 9.035 *10^11/2.0 *10^5

                          = 4.5 * 10^6

8 0
2 years ago
Read 2 more answers
Which of the following is the best definition of pseudoscience?
expeople1 [14]
The definition of pseudoscience is collection of beliefs or practices mistakenly regarded as being based on scientific method. which B is very similar to that. I believe the answer is A.

 Have a nice day. 
8 0
2 years ago
Read 2 more answers
Panuto: Sumulat ng isang halimbawa ng adyenda. Ipagpalagay mo na ikaw ay isang tagapayo. Ikaw
Degger [83]

Answer:

Sumulat lamang ng mga random na pangalan at sabihin ang "Appointment with (name)"

School Counselor ba ito?

8 0
2 years ago
How many moles of KCl will be<br> produced from 15.0 g of KClO3?
slega [8]

Answer:

0.12 mol KCl

Explanation:

2 KClO3 (s)   2 KCl (s) + 3 O2 (g)

15 g                x mol

x g KCl = 15 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]

x g KCl = 0.12 mol KCl

7 0
2 years ago
Read 2 more answers
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