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Assoli18 [71]
2 years ago
14

What are the respective central-metal oxidation state, coordination number, and overall charge on the complex ion in Na2[Cr(NH3)

2 (NCS)4]?
Chemistry
1 answer:
Elden [556K]2 years ago
6 0

Answer:

Central-metal oxidation state: +2

Coordination number: 6

Overall charge: -2

Explanation:

In the ion complex:

Na₂[Cr(NH₃)₂(NCS)₄]

The central-metal is Cr, the ligands are NH₃ and NCS.

The NH₃ is a neutral ligand, while NCS is an anionic ligand with -1 in charge.

The overall charge of the complex is:

2Na⁺ +  [Cr(NH₃)₂(NCS)₄]⁻² → <em>-2</em>

As NCS gives -1 in charge and there are four NCS, The Cr must be in <em>+2</em> of oxidation state to give an overall charge of -2.

As Cr is bonded to 2 NH₃ and 4 NCS, the coordination number is 2+4 = <em>6</em>

<em />

I hope it helps!

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What is the mass in grams of 6.022×1023 atoms of mass 16.00 amu?
german
16.00 g -------------- 6.02x10²³ atoms
?? g ----------------- 6.022x10²³ atoms

16.00 x (6.022x10²³) / 6.02x10²³ =

=> 16 g


7 0
2 years ago
A pharmacist–herbalist mixed 100 g lots o St. John’s wort containing the ollowing percentages o the active component hypericin:
Anna [14]

Answer:

strength of hypericin in mixture = 0.42 %

Explanation:

given data

each lot = 100 g

active component hypericin = 0.3%, 0.7%, and 0.25%

solution

we get here percent strength o hypericin in the mixture that is

Hypericin contribution lot 1 =  \frac{0.3}{100} × 100

Hypericin contribution lot 1 =  0.3 g

and

Hypericin contribution lot 2 = \frac{0.3}{100} × 100

Hypericin contribution lot 2 = 0.7 g

and

Hypericin contribution lot 3 = \frac{0.25}{100} × 100  

Hypericin contribution lot 3  = 0.25 g

so

total 300 g mixture of hypericin contain = 0.3 g + 0.7 g + 0.25 g

total 300 g mixture of hypericin = 1.25 g  

so here percent strength o hypericin in mixture is

strength of hypericin in mixture = \frac{1.25}{300} × 100  

strength of hypericin in mixture = 0.42 %

5 0
1 year ago
The ph of a solution that contains 0.818 m acetic acid (ka = 1.76 x 10-5) and 0.172 m sodium acetate is __________.
crimeas [40]
PH is calculated using <span>Handerson- Hasselbalch equation,

                                      pH  =  pKa  +  log [conjugate base] / [acid]

Conjugate Base  =  Acetate (CH</span>₃COO⁻)
Acid                    =  Acetic acid (CH₃COOH)
So,
                                      pH  =  pKa  +  log [acetate] / [acetic acid]

We are having conc. of acid and acetate but missing with pKa,
pKa is calculated as,

                                     pKa  =  -log Ka
Putting value of Ka,
                                     pKa  =  -log 1.76 × 10⁻⁵

                                     pKa  =  4.75
Now,
Putting all values in eq. 1,
                     
                                     pH  =  4.75 + log [0.172] / [0.818]

                                     pH  =  4.072
4 0
2 years ago
If the kinetic energy of a particle is equal to twice its rest mass, what is the velocity of the particle? Determine if relativi
ivann1987 [24]

Answer:

The velocity of the particle is 2 m/s,

Explanation:

Kinetic energy is defined as energy of the body due to its motion. It is given by :

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m = mass of the object

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We have , particle with mass m and its kinetic energy is twice its mass.

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8 0
2 years ago
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77julia77 [94]

Answer:

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(d) is correct option.

Explanation:

Given that,

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If the reaction is repeated with excess NaOH but with 1 mole of F₂

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Hence, The amount of NaF produced is doubled.

(d) is correct option.

6 0
2 years ago
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