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Pavel [41]
2 years ago
7

Match the theoretical motions of particles with their associated phases. Solid, Gas, Liquid. 1. oscillation about a fixed point

2. translation, vibration, rotation 3. rotation and vibration

Chemistry
2 answers:
podryga [215]2 years ago
6 0
The correct combination of <span>theoretical motions of particles with their associated phases is given below:

1) Solid : </span>oscillation about a fixed point . Because solids do vibrate (atoms/molecules of a solid oscillate around their mean positions)<span>
2) Gas : </span>translation, vibration, rotation. The gas molecules are free to rotate, oscillate & vibrate. <span>
3) Liquid: </span>rotation and vibration. The liquid molecules are free to rotate & vibrate.

A more clear pictures (at atomic & molecular level is shown below):

Viktor [21]2 years ago
3 0

Answer:1) Solid : oscillation about a fixed point .Because solids do vibrate (atoms/molecules of a solid oscillate around their mean positions)

2) Gas : translation, vibration, rotation. The gas molecules are free to rotate, oscillate & vibrate.

3) Liquid: rotation and vibration. The liquid molecules are free to rotate & vibrate.

Explanation:

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Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 1) H2(g)+12O2(g)⟶H2O
Bond [772]

Answer:

ΔH = -793,6 kJ

Explanation:

It is possible to obtain ΔH of this reaction using Hess's law that says you can sum the half-reactions ΔH to obtain the ΔH of the global reaction:

If half-reactions are:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁ = −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂ = +356.9 kJ  

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl(g) ΔH₃ = −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄ = −639.1 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅ = −44.0 kJ

The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:

(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ

+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ

-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ

-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ

-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ

= <em>XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)</em>

Where ΔH is:

ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ

<em>ΔH = -793,6 kJ</em>

I hope it helps!

5 0
2 years ago
A graduated cylinder holds 100 mL of water. A lead weight is dropped into the cylinder bringing the new volume up to 450 mL. If
dolphi86 [110]

11.43g/mL

Explanation:

Given parameters:

Volume of water in the graduated cylinder = 100mL

Volume of water + lead weight = 450mL

Mass of lead weight = 4000g

Unknown:

Density of the lead weight = ?

Solution:

Density is the mass per unit volume of a body.

  Density  = \frac{mass}{volume}

Volume of the lead weight = volume of water displaced

 Volume of lead weight = 450 - 100 = 350mL

Density = \frac{4000}{350}  = 11.43g/mL

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

6 0
2 years ago
6. Cross-cuts are best made with which of the following types of knife? A. Utility knife B. Scaler C. Paring knife D. Chef's kni
zaharov [31]

Answer:

A

Explanation:

Utility knife

8 0
2 years ago
Read 2 more answers
an alloy contains 56g of pure silver and 22g of pure copper what is the percentage(%) of silver in the alloy?
Lerok [7]
To get the ans divide 5600by 78 and there is ur answer
6 0
2 years ago
Read 2 more answers
If a penny is made of 3.11 grams of copper, how many atoms of copper are in the penny
Pie

Answer:

2.94x10²² atoms of Cu

Explanation:

We must work with NA to solve this, where NA is the number of Avogadro, number of particles of 1 mol of anything.

Molar mass Cu = 63.55 g/mol

Mass / Molar mass = Mol → 3.11 g / 63.55 g/m = 0.0489 moles

1 mol  of Cu has 6.02x10²³ atoms of Cu

0.0489 moles of Cu, will have (0.0489  .NA)/ 1 = 2.94x10²² atoms of Cu

8 0
2 years ago
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