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2 years ago

What is 2a²b + 6ab² factorised

2 answers:

4 0

Hey there :)

2a²b + 6ab²

Let us go step by step.

The common multiple between both is 2
2 x 1 = 2
2 x 3 = 6

The common variables are a and b, not a² and b² because both values do not have it

Therefore
2ab ( a + 3b ) is the factor

Dima020 [189]2 years ago

3 0

2ab(1a + 3b)

Hope this helps.

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During a catered lunch, an average of 4 cups of tea are poured per minute. The lunch will last 2 hours. How many gallons of tea

allsm [11]

The answer is 30.
There are 16 cups in a gallon. And 120 minutes in 2 hours. so multiple
16*120 which is 480. Then divide 480/120 and get 30 as your answer

8 0

2 years ago

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a railway car is 3.2m in diameter and 17.2m long. estimate the cost of painting the outside of the railway car, if a can of pain

Iteru [2.4K]

The awnser would be 43.768

7 0

2 years ago

The average time taken to complete an exam, X, follows a normal probability distribution with mean = 60 minutes and standard dev

k0ka [10]

Answer: b. 0.8413

Step-by-step explanation:

Given : The average time taken to complete an exam, X, follows a normal probability distribution with $\mu=60\text{ minutes}$ and $\sigma=30\text{ minutes}$ .

Then, the probability that a randomly chosen student will take more than 30 minutes to complete the exam will be :-

$P(x>30)=P(z>\dfrac{30-60}{30})\ \ [\because\ z=\dfrac{x-\mu}{\sigma} ]\\\\=P(z>-1)=P(z-z)=P(Z$

[using z-value table]

Hence, the probability that a randomly chosen student will take more than 30 minutes to complete the exam = 0.8413

3 0

2 years ago

A box of buttons contains the same number of each type of button. It contains 220g of buttons

ra1l [238]

Answer:

a) 18 button a buttons are required to fill the bag.

b) 12 button b buttons are required to fill the bag.

c) There are 11 buttons of each type in the box containing 220 g of buttons.

Step-by-step explanation:

Complete Question

Two button types, button a weighing 8 grams and button b weighing 12 grams. The buttons are sold in bags. Each bag contains 144 grams of buttons.

a) How many of button a are needed to fill one bag?

b) How many of button b are needed to fill one bag?

c) A box of buttons contains the same number of each type of button it contains 220g of buttons. How many of each type of button are in the box.

Solution

a) A bag contains 144 grams of buttons.

Button a weighs 8 grams per button.

Total number of button a buttons required to fill up the bag = (144/8) = 18 button a buttons.

b) A bag contains 144 grams of buttons.

Button b weighs 12 grams per button.

Total number of button b buttons required to fill up the bag = (144/12) = 12 button a buttons.

c) A box of buttons weighing 220 g contains the same number of each type of button.

Let this number be n.

This means the Total weight of button a buttons in this box = 8n

total weight of button b buttons in this box = 12n

Sum total of the weight of the buttons = 8n + 12n = 20n

20n = 220

n = (220/20) = 11.

This means there are 11 buttons of each type in the box containing 220 g of buttons.

Hope this Helps!!!

6 0

2 years ago

Fiber X cereal is 55% fiber. Fiber Max cereal is 70% fiber. Sheldon combines an amount of the two cereals in a single bowl of mi

almond37 [142]

Answer:

There are 4 ounces of Fiber X cereal in the mix

Step-by-step explanation:

Lets n be the amount of ounces of Fiber X in the mix. Since there are a total of 12 ounces in the mix, then, on terms of n, there are 12-n ounces of Fiber Max on it.

Since 65% of the mix is Fiber, then there are 12*0.65 = 7.8 ounces of Fiber. We can also obtain this value if we take the proportions of Fiber in each cereal of the mix (in terms of n), so that we can obtain the true value of n

we have

7.8 = n *0.55 + (12-n)*0.7 = 0.55n + 8.4 -0.7 n = 8.4-0.15n

Therefore

0.15 n = 0.6

n = 0.6/0.15 = 4

As a consecuence, there are 4 ouces of Fiber X cereal in the mix.

6 0

2 years ago