Answer:
0
Step-by-step explanation:Velocity at t= 0s is 20m/s and the velocity at t= 10s is 20m/s.
a= 20-20/ 10s
a=0m/s
Answer:
In kJ/kg.K - 1.005 kJ/kg degrees Kalvin.
In J/g.°C - 1.005 J/g °C
In kcal/ kg °C 0.240 kcal/kg °C
In Btu/lbm-°F 0.240 Btu/lbm degree F
Step-by-step explanation:
given data:
specific heat of air = 1.005 kJ/kg °C
In kJ/kg.K
1.005 kJ./kg °C = 1.005 kJ/kg degrees Kelvin.
In J/g.°C

In kcal/ kg °C

For kJ/kg. °C to Btu/lbm-°F
Need to convert by taking following conversion ,From kJ to Btu, from kg to lbm and from degrees C to F.

1.005 kJ/kg C = 0.240 Btu/lbm degree F
Answer: 0.79
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Answer:
Step-by-step explanation:
Given that: The perimeter of a square is: 32x - 12.8
As we all know that, the formula to find the perimeter of a square is:
Sum of the 4 side = 4* length of the side
=> the length of 1 side: The perimeter of a square / 4
In this situation, we have length of 1 side side is:
(32x - 12.8) / 4
= 32/4x - 12.8/4
= 8x - 3.2
The 1st equivalent expressions for the perimeter: 4 *(8x - 3.2)
The 2nd equivalent expressions for the perimeter: (8x - 3.2) + (8x - 3.2) + (8x - 3.2) + (8x - 3.2)
The 3rd equivalent expressions for the perimeter: 2*(8x - 3.2) + 2*(8x - 3.2)