Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

$C(n,r)= \frac{n!}{r!(n-r)!}$

where n is a total number of choices ( 11 )
and r is number chosen out of those choices (4)
so

C(11,4)= \frac{11!}{4!(11-4)!}

She has 330 possible choices to come home with 4 pieces of jewelry

5 0

2 years ago

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Liam had \$250$250dollar sign, 250. Then, he and his classmates bought a present for their teacher, evenly splitting the \$p$pdo

Nostrana [21]

Answer: 250- 9/24

250, minus, start fraction, p, divided by, 24, end fraction dollars left.

Step-by-step explanation:

Liam had \$250$250dollar sign, 250. Then, he and his classmates bought a present for their teacher, evenly splitting the \$p$pdollar sign, p cost among the 242424 of them.

3 0

2 years ago

a school district requires all graduating seniors to take a mathematics test. This year, the rest scores were approximately norm

Klio2033 [76]

A score of 85 would be 1 standard deviation from the mean, 74. Using the 68-95-99.7 rule, we know that 68% of normally distributed data falls within 1 standard deviation of the mean. This means that 100%-68% = 32% of the data is either higher or lower. 32/2 = 16% of the data will be higher than 1 standard deviation from the mean and 16% of the data will be lower than 1 standard deviation from the mean. This means that 16% of the graduating seniors should have a score above 85%.

3 0

2 years ago