Which of Newton’s laws of accounts for the following statement?

(d) A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scat

irakobra [83]

QUESTION:-A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scattered from the paper and reflected from the mirror.
Describe how scattering by paper and reflection by a mirror are different from each other.

ANSWER: Scattering sends or reflects light from each point on the object in all directions, whereas reflection sends light from each point on the object in one direction only (or to one point)

5 0

2 years ago

A woman is straining to lift a large crate, without success because it is too heavy. We denote the forces on the crate as follow

Ymorist [56]

Answer:

Explanation:

Given

Force P is acting upward

C is vertical contact Force

W is the weight of the crate

As P is unable to move the Block therefore Normal reaction keeps on acting on block

thus we can say that

P-W+C=0

P=W-C

7 0

2 years ago

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A constant torque of 200Nm turns a wheel about its centre. The moment of inertia of it about the axis is 100kgm^s . Find the kin

AleksAgata [21]

It would turn 160 degrees after twenty truns

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3 0

2 years ago

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A 1.25 in. by 3 in. rectangular steel bar is used as a diagonal tension member in a bridge truss. the diagonal member is 20 ft l

pentagon [3]

Answer:

axial stress in the diagonal bar =36,000 psi

Explanation:

Assuming we have to find axial stress

Given:

width of steel bar: 1.25 in.

height of the steel bar: 3 in

Length of the diagonal member = 20ft

modulus of elasticity E= 30,000,000 psi

strain in the diagonal member ε = 0.001200 in/in

Therefore, axial stress in the diagonal bar σ = E×ε

= 30,000,000 psi× 0.001200 in/in =36,000 psi

5 0

2 years ago

How many ternary strings of length 2 n are there in which the zeroes appear only in odd-numbered positions?

Rashid [163]

In a string of length $2n$ , there are exactly $n$ odd-numbered posiitons. In the remaning $n$ even-numbered positions, we want to choose from only two possible digits, either a 1 or a 2. This means there are $2^n$ such ternary strings.

8 0

2 years ago