A point with an ordinate of 0 belongs to the graph of the equation 12x–15y=132. Find the abscissa of that point.

2 answers:

8 0

We know that
the ordinate is the y coordinate and the abscissa is the x coordinate

we have that
12x–15y=132
for y=0
x=?
12x-15*0=132------> 12x=132--------> x=11

the point is (11,0)

the answer is
x=11

nexus9112 [7]2 years ago

7 0

Answer:

Abscissa=11

Step-by-step explanation:

An ordered pair consists of two terms—the abscissa (horizontal, usually x) and the ordinate (vertical, usually y)—which define the location of a point in two-dimensional rectangular space.

We are given a equation 12x-15y=132

y=0 we have to find x

Putting y=0, we get

12x=132

⇒ x=132/12

=11

Hence, abscissa=11

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Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

$\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}
\\\\\\
\boxed{b=\cfrac{200}{tan(16.38^o)}-a}
\\\\\\
tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\
-------------------------------\\\\
\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}$

make sure your calculator is in Degree mode.