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Evgesh-ka [11]
2 years ago
9

Consider the following system of equations: 10 + y = 5x + x2 5x + y = 1 The first equation is an equation of a . The second equa

tion is an equation of a .
Mathematics
2 answers:
hammer [34]2 years ago
8 0

Answer:

parabola

line

Step-by-step explanation:

next couple ones are

0,1,2

then

1, -11 , 56

youre welcome

aleksley [76]2 years ago
5 0

Answer: The first equation is an equation of a parabola. The second equation is an equation of a line.

Explanation:

The first equation is,

10+y=5x+x^2

In this equation the degree of y is 1 and the degree of x is 2. The degree of both variables are not same. Since the coefficients of y and higher degree of x is positive, therefore it is a graph of an upward parabola.

The second equation is,

5x+y=1

In this equation the degree of x is 1 and the degree of y is 1. The degree of both variables are same. Since both variables have same degree which is 1, therefore it is linear equation and it forms a line.

Therefore, the first equation is an equation of a parabola. The second equation is an equation of a line.

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On this graph, 4:00 p.m. occurs at 16 hours after midnight, and 6:00 p.m. occurs at 18 hours after midnight. Which statements ar
KatRina [158]

Answer:

TRUE OPTIONS ARE:

<em>"The temperature increased until 4:00 p.m. "</em>

<em>"The temperature decreased after 6:00 p.m. "</em>

<em>"The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m."</em>

Step-by-step explanation:

<em>graph attached and complete question below:</em>

<em>Which statements are true about the temperatures Luis  recorded on the graph? Check all that apply. </em>

  • <em>The temperature increased until 4:00 p.m. </em>
  • <em>The temperature was not recorded between 4:00 p.m.  and 6:00 p.m. </em>
  • <em>The temperature decreased after 6:00 p.m. </em>
  • <em>The temperature increased and then decreased before  holding constant. </em>
  • <em>The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m.</em>

<em />

Until 1600 hours, the graph increases, so we can say temperature increased until 4.00 pm (FIRST OPTION TRUE).

From 1600 to 1800 hours (4 - 6pm), the temperature stayed same (horizontal line). This doesn't mean the temperature wasn't recorded. (2nd OPTION FALSE).

After 1800 hours (6pm), the line goes downward, so temperature decreased after 6 pm. (3rd OPTION TRUE).

If you look at the temperature graph, we can see temperature increased, then increased more, then constant, then decreased. Thus the 4th option isnt true. (4th OPTION FALSE).

Before 12, the increase isn't as sharp as after 12. After 12 temperature increase has more slope, so this increase is more. (5th OPTION TRUE).

7 0
2 years ago
Read 2 more answers
The heights of 1000 students are approximately normally distributed with a mean of 174.5 centimeters and a standard deviation of
yuradex [85]
A. The mean and standard deviation.

The mean of a sampling distribution is approximately equal to the mean of the population. Given that the mean of the population is equal to 174.5, the mean of the sampling distribution is also this value.

The standard deviation of a sample distribution is equal to,

                u(m) = u/sqrt n

Substituting the known values,

               u(m) = 6.9 / sqrt 25 = 1.38

b. Get the z-score of both items,
         
      z-score = (data point - mean) / standard deviation

 z-score of 172.5
     z-score = (172.5 - 174.5) / 1.38 = -1.49
This translates to 0.068.

z-score of 175.8
   z-score = (175.8 - 174.5) / 1.38 = 0.94
This translates to 0.83. 

The difference between the two z-scores is 0.762. 

 The number of samples with this height is 0.762(200) which is equal to approximately 152.

c. z-score of 172 centimeters
   
    z-score = (172 - 174.5) / 1.38
  
    z-score = -1.81
This translates to 0.03.

The number of people with this height from the sample is (0.03)(200) = 6
8 0
2 years ago
Find a b if a = 3i + 8j and b = -0.5i -4j.
Gekata [30.6K]

Answer:

-33.5

Step-by-step explanation:

So this is a dot products vector problem, so the i and j represent x and y or horizontal and vertical components. So you multiple 3i and -0.5i and then separately multiply 8j and -4j. You get -1.5 and -32. Now all you have to do is add them and you get -33.5.

Basically in short:

1. Multiply the “i’s”.

2. Multiply the “j’s”.

3. Add the two products together.

HOPE THIS HELPS !! :-)

3 0
2 years ago
Read 2 more answers
What is the measure in radians for the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm?
ololo11 [35]

central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm is 0.9 radians

Step-by-step explanation:

We need to find the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm.

arc length l== 7.2 cm

radius =r= 8 cm

central angle=Ф = ?

The formula used is:

l=r\theta

Putting values:

\theta=\frac{l}{r}\\ \theta=\frac{7.2}{8} \\\theta=0.9\,\,radians

So, central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm is 0.9 radians

Keywords: central angle of circle

Learn more about central angle of circle at

  • brainly.com/question/8618791
  • brainly.com/question/1952668
  • brainly.com/question/2860697

#learnwithBrainly

4 0
2 years ago
In the diagram, the length of segment QV is 15 units. What is the length of segment TQ? 4 units 11 units 14 units 15 units
vivado [14]
We know tht QV = 15 and TQ = TS, QV = SV;
4 x - 1 = 15
4 x = 15 + 1
4 x = 16
x = 16 : 4 = 4
After that:
TQ = 3 * 4 + 2 = 12 + 2 = 14
Answer:
C )  14 units.
3 0
2 years ago
Read 2 more answers
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