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Zielflug [23.3K]
2 years ago
14

The box office took in a total of $2905 in paid admissions for the high-school musical. Adult tickets cost $8 each, and student

tickets cost $3 each. If 560 people attended the show, how many were students? Let s = the number of students attending, and let a = the number of adults attending. Which two equations can be used to solve this problem? Select the two that apply.
Mathematics
1 answer:
Svet_ta [14]2 years ago
7 0
There are no equations to choose from but it should look like the following.

a= # of adult tickets
s= # of student tickets

QUANTITY EQUATION
a + s= 560

COST EQUATION
$8a + $3s= $2905

***If you have to also solve for the number of adults and students, here are the steps.

STEP 1:
multiply quantity equation by -8

-8(a + s)= -8(560)
-8a - 8s= -4480

STEP 2:
add cost equation and step 1 equation

$8a + $3s= $2905
-8a - 8s= -4480
a term cancels out to zero
-5s= -1575
divide both sides by -5
s= 315 students

STEP 3:
substitute s=315 in quantity equation
a + s= 560
a + 315= 560
subtract 315 from both sides
a= 245 adults

ANSWER:
Quantity Equation
a + s= 560

Cost Equation
$8a + $3s= $2905

Hope this helps! :)
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At a local grocery store, apples cost $0.50 each and bananas cost $0.30 each. The expression 0.50x + 0.30y can be used to find t
JulsSmile [24]

(1) x represents the number of apples bought, y represents the number of bananas.

(2) each term represents the total costs of a given fruit, so 0.50x is the total cost of apples and 0.30y is total cost of bananas.

(3) The coefficients are unit prices: coefficient 0.50 is the price of 1 apple, 0.30 is the price of 1 banana.

3 0
1 year ago
After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an
galben [10]

Answer:

y=32000(1+0.08)^x

Step-by-step explanation:

Exponential growth function is y=a(1+r)^x

Where 'a' is the initial population

r is the rate of growth and x is the time period in years

a steady population of 32,000. So initial population is 32,000

an increase of 8% per year. the rate of increase is 8% that is 0.08

a= 32000 and r= 0.08

Plug in all the values in the general equation

y=a(1+r)^x

y=32000(1+0.08)^x

y=32000(1+0.08)^x

4 0
1 year ago
Read 2 more answers
Mrs. Garcia borrowed some money at the rate of 4% per annum for the first year, at the rate of 6% pe r annum for the next 2 year
s2008m [1.1K]

Answer: ₱40,909.1

Step-by-step explanation:

Given data:

Rate for first year = 4%

Rate for next two years = 6%

Rate for the next 3 years = 7.5%

Interest paid back after 5years = ₱ 15,750

Solution:

How much did she borrow.

= let the sum borrowed be P

= P * 4 / 100

= 4P/100

= 1P/25.

For the next two years

= P* 6 * 2/100

= 12P/100

= 3P/25

For the next 3years

= P* 7.5*3/100

= 22.5P/100

= 9P/40.

1P/25 + 3P/25 + 9P/40 = 15750

77P/200 = 15750

P = 15750 * 200 / 77

P = 315,0000/77

P = ₱40,909.1

The amount borrowed is ₱40,909.1

5 0
2 years ago
A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st
Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                          P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample credit hours per quarter = 15.2 credit hours

             s = sample standard deviation = 2.3 credit hours

             n = sample of students = 250

             \mu = population mean credit hours per quarter

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < t_2_4_9 < 1.96) = 0.95  {As the critical value of t at 249 degree of

                                        freedom are -1.96 & 1.96 with P = 2.5%}  

P(-1.96 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{s}{\sqrt{n} } } , \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ]

                  = [ 15.2-1.96 \times {\frac{2.3}{\sqrt{250} } } , 15.2+1.96 \times {\frac{2.3}{\sqrt{250} } } ]

                  = [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

<em>The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.</em>

8 0
1 year ago
Ronnie wants to lower his utility bills to save money on his monthly expenses. He discovers that if he replaces his water heater
Soloha48 [4]

Alright, lets get started.

Last year, Ronnie's utility expenses were = 1935.67 $

After switching to electric water heater to solar water heater, his yearly utility bills get reduced.

This year, Ronnie's utility expenses are = 862.40 $

So the difference on utility bills Ronnie saved = 1935.67 - 862.40

so, difference Ronnie saved = 1073.27 $

So, the percentage of amount Ronnie saved = \frac{1073.27}{1935.67} *100

Percentage of amount Ronnie saved = 55.45 %    

Hence, 55.45 % Ronnie save on his utlility bills by switching to a solar water heater.   :    Answer

Hope it will help :)


5 0
1 year ago
Read 2 more answers
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