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Zielflug [23.3K]
2 years ago
14

The box office took in a total of $2905 in paid admissions for the high-school musical. Adult tickets cost $8 each, and student

tickets cost $3 each. If 560 people attended the show, how many were students? Let s = the number of students attending, and let a = the number of adults attending. Which two equations can be used to solve this problem? Select the two that apply.
Mathematics
1 answer:
Svet_ta [14]2 years ago
7 0
There are no equations to choose from but it should look like the following.

a= # of adult tickets
s= # of student tickets

QUANTITY EQUATION
a + s= 560

COST EQUATION
$8a + $3s= $2905

***If you have to also solve for the number of adults and students, here are the steps.

STEP 1:
multiply quantity equation by -8

-8(a + s)= -8(560)
-8a - 8s= -4480

STEP 2:
add cost equation and step 1 equation

$8a + $3s= $2905
-8a - 8s= -4480
a term cancels out to zero
-5s= -1575
divide both sides by -5
s= 315 students

STEP 3:
substitute s=315 in quantity equation
a + s= 560
a + 315= 560
subtract 315 from both sides
a= 245 adults

ANSWER:
Quantity Equation
a + s= 560

Cost Equation
$8a + $3s= $2905

Hope this helps! :)
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A charity fair raised $6,000 by selling 500 lottery tickets. There were two types of lottery tickets: A tickets cost $10 each, a
julsineya [31]





x= A ticket 
y=b ticket
x+y=500
10x+60y=6000 
-------------------
   10x+60y=6000 
-  x+y=500 (*10) ---> 10x+10y=5000
-------------------
   10x+60y=6000
-  10x+10y=5000
-------------------
50y=1000
y=1000/50
y=20
b ticket =20

x+y=500
x+20=500
x=500-20
x=480
a ticket=480
 answer is the last option , 
6 0
2 years ago
3. What unit would you use to measure the weight of a school bus? *
larisa [96]

Answer:

Tons

Step-by-step explanation:

A school bus should be weighed in tons due to the fact that it definitely weighs more than a few pounds.

4 0
2 years ago
Find the mean, median and mode of the weights of the people shown. 105kg 53kg 76kg 91kg 120kg 61kg 55kg 98kg 61kg
Yuliya22 [10]
First, you need to put them in order
53kg, 55kg, 61kg, 61kg, 76kg, 91kg, 98kg, 105kg, 120kg

For mean, you add them all up and divide by the amount of numbers (9)
720/9 = 80

For median, you find the middle number (76kg)

For mode, you find the number that appears the most (61kg)

Mean: 80
Median: 76
Mode: 61
5 0
2 years ago
Read 2 more answers
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

and the first monomial is equal to 15x^{11} -----> coefficient is 15

So

possible values of p are 1, and\ 3

possible values of q are 1, 3, 5, and\ 15

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


3 0
2 years ago
Read 2 more answers
Jada invests $590 in a money market account her account pays 7.2% simple interest if she does not add or withdraw any money how
denis-greek [22]

Answer:

$169.92

Step-by-step explanation:

<em>Multiply Yearly Interest By How Many Years</em>

7.2 * 4 = 28.8

<em>Take 28.8 Percent Of Amount Of Money In The Account</em>

28.8 percent of 590 = 169.92

3 0
2 years ago
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