If RB = 4 and OR = 3, then OB = 5 7 2√3
2 answers:
The complete question in the attached figure
we know that
triangle OBR is a right triangle
so
<span>applying the Pythagorean theorem
</span>OB²=OR²+RB²----> OB²=3²+4²-----> 25
OB=√25-----> OB=5 units
the answer is
OB=5 units
we know that
triangle OBR is a right triangle
so
<span>applying the Pythagorean theorem
</span>OB²=OR²+RB²----> OB²=3²+4²-----> 25
OB=√25-----> OB=5 units
the answer is
OB=5 units
Answer:
OB = 5 units
Step-by-step explanation:
OPtion I is right
Given in the picture is a circle.
AB is a chord, O is the centre of the circle
OR is drawn perpendicular to AB.
Given that OR =3, and RB =4
Since ORB is a right triangle with known legs we can find the hypotenuse OB using Pythagorean theorem
Hence radius of the circle = 5 units.
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