All categories

2 years ago

If RB = 4 and OR = 3, then OB = 5 7 2√3

Mathematics

2 answers:

pogonyaev2 years ago

5 0

The complete question in the attached figure

we know that

triangle OBR is a right triangle
so
applying the Pythagorean theorem

OB²=OR²+RB²----> OB²=3²+4²-----> 25
OB=√25-----> OB=5 units

the answer is
OB=5 units

LekaFEV [45]2 years ago

5 0

Answer:

OB = 5 units

Step-by-step explanation:

OPtion I is right

Given in the picture is a circle.

AB is a chord, O is the centre of the circle

OR is drawn perpendicular to AB.

Given that OR =3, and RB =4

Since ORB is a right triangle with known legs we can find the hypotenuse OB using Pythagorean theorem

$OB^2=OR^2+RB^2=3^2+4^2 =25\\OB =5$

Hence radius of the circle = 5 units.

You might be interested in

Kendal bought x boxes of cookies to bring to a party. Each box contains 12 cookies. She decides to keep two boxes for herself. S

Georgia [21]

Answer:

Step-by-step explanation:

Total number of boxes of cookies that Kendal bought to bring to the party is x.

Each box contains 12 cookies. This means that total number of cookies in x boxes would be

12 × x = 12x

She decides to keep two boxes for herself. This means that the total number of cookies that she kept for herself would be

12 × 2 = 24 cookies

She brings 60 cookies to the party.

The equation that can be used to find the number of boxes, x, Kendal bought would be

12x = 24 + 60

12x = 84

x = 84/12 = 7 boxes

6 0

2 years ago

If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal

Vera_Pavlovna [14]

Answer:

y''=-1.26

Step-by-step explanation:

We are given that $2x^2+y^2=17$

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

$4x+2yy'=0$

$2x+yy'=0$

$yy'=-2x$

$y'=-\frac{2x}{y}$

Again differentiate w.r.t.x

Then , we get

$2+(y')^2+yy''=0$ $(u\cdot v)'=u'v+v'u)$

$2+(y')^2+yy''=0$

Using value of y'

$yy''=-2-(-\frac{2x}{y})^2$

$y''=-\frac{2+(-\frac{2x}{y})^2}{y}$

Substitute x=2 and y=3

Then, we get $y''=-\frac{2+(\frac{4}{3})^2}{3}$

$y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}$

Hence,y''=-1.26

6 0

2 years ago

Fill in missing information to make the equality true: (... +2a)2 = … +12ab2+4a2.

BigorU [14]

Answer:

I suppose it should be

6b² and (6b²)²

6b² and 36 $b^{4}$

Step-by-step explanation:

(a+b)² = a² + 2ab + b²

therefore

(6b²+2a)² = (6b²)² + 12ab² + 4a²

3 0

2 years ago

Read 2 more answers

A group of kids just finished trick-or-treating. The number of pieces of candy collected by each of the 5 kids

NemiM [27]

Answer:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808$

And the answer for this case would be :

$s= 3.81$ after round the value

Step-by-step explanation:

We have the following data set given:

31, 33, 36, 41, 34

If we want to find the standard deviation we need to find first the sample mean with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35$

Now we can find the sampel deviation with this formula:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808$

And the answer for this case would be :

$s= 3.81$ after round the value

6 0

2 years ago

Andrew believes the honor roll students at his school have an unfair advantage in being assigned to the math class they request.

Artist 52 [7]

Honor roll Not on honor roll Total
Received math class requested 315 64 379
Did not get math class requested 41 80 121
Total 356 144 500

Honor roll: request granted: 315/356 = 0.88 x 100% = 88%
Not Honor roll request granted: 64/144 = 0.44 x 100% = 44%

Honor roll students were given preference in granting request than those not in the honor roll.

5 0

2 years ago