answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lina2011 [118]
2 years ago
15

How many of the following are compounds? H2O, N2O4, NaOH, MnO2, HF

Chemistry
2 answers:
soldi70 [24.7K]2 years ago
7 0
Element= all of the same type of substance
Compound= different substances chemically bonded
Mixture= different substances not chemically bonded

so they are all compounds
lukranit [14]2 years ago
4 0
Im pretty sure all of them are compounds

You might be interested in
A mass spectrometer has determined the mass and abundances of all isotopes of an unknown element. The first isotope has a mass o
shepuryov [24]

Answer:

I believe it is Potassium (K)

Explanation:

I did the math on a calculator and it was the closest atomic mass to potassium.

5 0
2 years ago
An atom of lithium-7 has an equal number of
slavikrds [6]
The answer is (2). The Lithium has 3 protons and 4 neutrons. For every neutral atom, it will have the same number of protons and electrons. Because the proton has one positive charge and electron has one negative charge and neutron does not have charge.
8 0
2 years ago
What is the ph of a solution made by combining 157 ml of 0.35 m nac2h3o2 with 139 ml of 0.46 m hc2h3o2? the ka of acetic acid is
ExtremeBDS [4]
The first step is to calculate the molarity of each compound:
final volume of solution = 157 + 139 = 296 mL
molarity of <span>nac2h3o2 = (157 x 0.35) / 296 = 0.1856 molar
molarity of </span><span>hc2h3o2 = (139 x 0.46) / 296 = 0.216 molar

Then, we calculate the pH as follows:
pKa of acetic acid = -log(</span><span>1.75 × 10^-5) = 4.7569
pH = pKa + </span><span> log ([salt] / [acid]) 
     = </span>4.7569 + log(0.1856 / 0.216)
     = 4.691
6 0
2 years ago
What element is used in bright flashing advertising signs
Sergeu [11.5K]
The element used in advertising signs is neon.
4 0
2 years ago
The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this
dimaraw [331]

Answer:

C₄F₈

Explanation:

Using their mole ratio to compute their mass

molar mass of carbon = 12.0107 g/mol

molar mass of fluorine gas = 37.99681

let x = mass of carbon

given mass of fluorine = 1.70 g

x / 12.01067 = 1.70 / 37.99687

cross multiply

x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g

mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g

number of mole of CF₂ = 8.93 g / 2.23688 = 3.992 approx 4

molecular formula of CF₂ = 4 (CF₂) = C₄F₈

3 0
2 years ago
Other questions:
  • Which statement describes the transfer of heat energy that occurs when an ice cube is added to an insulated container with 100 m
    9·1 answer
  • There are two types of nucleic acids, dna and rna. nearly all organisms use dna, not rna, as the central repository for genetic
    15·1 answer
  • What do you do with unused (excess) chemicals that are taken from reagent bottles?
    13·1 answer
  • If a gas at 25.0 °C occupies 3.60 liters at a pressure of 1.00 atm, what will be its volume at a pressure of 2.50 atm?
    12·2 answers
  • Avogadro’s number is a constant that helps scientists count atoms and molecules. It is approximately equal to 602,200,000,000,00
    11·2 answers
  • Percentage of carbon in CCl^4
    7·2 answers
  • QUESTION 18 Solid aluminum and gaseous oxygen react in a combination reaction to produce aluminum oxide: 4Al (s) 3O 2 (g) 2Al 2O
    15·1 answer
  • A phosphorus atom with 4 bonds has a charge of ___.
    6·1 answer
  • sekiranya kutu tinggal di badan arnab dan menghisap darah arnab , apakah jenis interaksi antara kutu dengan arnab ?​
    5·1 answer
  • The enthalpy of Sodium is 235 calories. The enthalpy Chlorine is 435 calories. The enthalpy of Sodium chloride 670 joules, what
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!