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yarga [219]
2 years ago
5

A mass spectrometer has determined the mass and abundances of all isotopes of an unknown element. The first isotope has a mass o

f 38.96amu (93.28%) and the second a mass of 40.96amu (6.72%). Calculate the average atomic mass and identify the unknown element, WRITE ONLY THE SYMBOL FOR YOUR ANSWER.
Chemistry
1 answer:
shepuryov [24]2 years ago
5 0

Answer:

I believe it is Potassium (K)

Explanation:

I did the math on a calculator and it was the closest atomic mass to potassium.

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The balanced equation shows how sodium chloride reacts with silver nitrate to form sodium nitrate and silver chloride. NaCl + Ag
Verdich [7]
<span>NaCl First calculate the molar mass of NaCl and AgNO3 by looking up the atomic weights of each element used in either compound Sodium = 22.989769 Chlorine = 35.453 Silver = 107.8682 Nitrogen = 14.0067 Oxygen = 15.999 Now multiply the atomic weight of each element by the number of times that element is in each compound and sum the results For NaCl 22.989769 + 35.453 = 58.44277 For AgNO3 107.8682 + 14.0067 + 3 * 15.999 = 169.8719 Now calculate how many moles of each substance by dividing the total mass by the molar mass For NaCl 4.00 g / 58.44277 g/mol = 0.068443 mol For AgNO3 10.00 g / 169.8719 g/mol = 0.058868 Looking at the balanced equation for the reaction, there is a 1 to 1 ratio in molecules for the reaction. Since there is a smaller number of moles of AgNO3 than there is of NaCl, that means that there will be some NaCl unreacted, so the excess reactant is NaCl</span>
8 0
2 years ago
A solution is prepared by adding 6.24 g of benzene (C 6H 6, 78.11 g/mol) to 80.74 g of cyclohexane (C 6H 12, 84.16 g/mol). Calcu
tekilochka [14]

Answer:

x_B=0.0769

m=0.990m

Explanation:

Hello,

In this case, we can compute the mole fraction of benzene by using the following formula:

x_B=\frac{n_B}{n_B+n_C}

Whereas n accounts for the moles of each substance, thus, we compute them by using molar mass of benzene and cyclohexane:

n_B=6.24g*\frac{1mol}{78.11g}=0.0799mol\\ \\n_C=80.74g*\frac{1mol}{84.16g} =0.959mol

Thus, we compute the mole fraction:

x_B=\frac{0.0799mol}{0.0799mol+0.959mol}\\ \\x_B=0.0769

Next, for the molality, we define it as:

m=\frac{n_B}{m_C}

Whereas we also use the moles of benzene but rather than the moles of cyclohexane, its mass in kilograms (0.08074 kg), thus, we obtain:

m=\frac{0.0799mol}{0.08074kg}=0.990mol/kg

Or just 0.990 m in molal units (mol/kg).

Best regards.

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Answer:

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