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vladimir1956 [14]
2 years ago
3

Before a trip from new york to boston, the pressure in an automobile tire is 1.8 atm at 20.°c. at the end of the trip, the press

ure gauge reads 1.9 atm. what is the new celsius temperature of the air inside the tire? (assume tires with constant volume.) answers
Chemistry
1 answer:
WARRIOR [948]2 years ago
3 0
Gay-Lussac's law gives the relationship between pressure of gas and temperature. It states for a fixed amount of gas, the pressure of gas is directly proportional to temperature at constant volume. 
P / T = k 
where P - pressure, T - temperature in Kelvin and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - temperature in Kelvin - 20 °C + 273 = 293 K
substituting the values in the equation 
\frac{1.8 atm}{293 K} =  \frac{1.9 atm}{T}
T = 309 K 
new temperature in celcius scale - 309 K - 273 = 36 °C
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45.0 g of Ca(NO3)2 are used to create a 1.3 M solution. What is the volume of the solution
Stells [14]
As we know that Molarity is given as,

                                       M = moles / V 
Solving for V,
                                        V = moles / M ------------------(1)
Also, moles is equal to,
                                       moles = mass / M. mass -------------(2)
puting value of moles from eq. 2 into eq. 1,
                                       V = (mass / M.mass) / M
Putting values,
                                       V = (45 g / 164 g/mol) / 1.3 mol/dm³

                                       V = 0.21 dm³ 
6 0
2 years ago
Describe the process used to measure out a specific mass of a solid
Svetlanka [38]
Although the process varies slightly from one material to another, the general process is as follows:

1) Choose an appropriate container for the solid. This may be a petri dish or a beaker in which you want to prepare the solution of the solid or any other lab equipment.

2) Place the container on a mass balance, then turn the balance on. The mass balance will automatically zero-out the mass of the container, so that any mass that you add on the container will be the mass of the solid. Alternatively, you may first measure the mass of the empty container alone.

3) Add the solid using a lab spatula. The solid should be added more slowly when the reading on the scale comes close to the desired value.

4) Remove the container from the mass balance after the desired amount of solid has been added.
7 0
2 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N2O4(g) 2N
Amanda [17]

Answer : The correct option is, (a) 0.44

Explanation :

First we have to calculate the concentration of N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

Now we have to calculate the dissociated concentration of N_2O_4.

The balanced equilibrium reaction is,

                             N_2O_4(g)\rightleftharpoons 2NO_2(aq)

Initial conc.           1.0 M          0

At eqm. conc.     (1.0-x) M    (2x) M

As we are given,

The percent of dissociation of N_2O_4 = \alpha = 28.0 %

So, the dissociate concentration of N_2O_4 = C\alpha=1.0M\times \frac{28.0}{100}=0.28M

The value of x = C\alpha = 0.28 M

Now we have to calculate the concentration of N_2O_4\text{ and }NO_2 at equilibrium.

Concentration of N_2O_4 = 1.0 - x  = 1.0 - 0.28 = 0.72 M

Concentration of NO_2 = 2x = 2 × 0.28 = 0.56 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Now put all the values in this expression, we get :

K_c=\frac{(0.56)^2}{0.72}=0.44

Therefore, the equilibrium constant K_c for the reaction is, 0.44

8 0
2 years ago
Write the balanced half-equation describing the oxidation of mercury to hgo in a basic aqueous solution. Please include the stat
Cloud [144]

Answer:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Explanation:

Hello,

In this case, mercury (II) oxide (HgO) is obtained via the reaction:

Hg(l)+O_2\rightarrow HgO

Nonetheless, since it is a reaction carried out in basic solution, mercury's half-reaction only, must be:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Thus, it is seen that OH ionis should be added due to the basic aqueous solution considering that 2 electrons are transferred from 0 to 2 in mercury.

Best regards.

8 0
2 years ago
Please help!!
Sati [7]

In a chemical reaction, the limiting reagent is the chemical being used up while the excess reactant is the chemical left after the reaction process.

Before calculating the limiting and excess reactant, it is important to balance the equation first by stoichiometry.

C25N3H30Cl + NaOH = C25N3H30OH + NaCl

Since the reaction is already balanced, we can now identify which is the limiting and excess reagent.

First, we need to determine the number of moles of each chemical in the equation. This is crucial for determining the limiting and excess reagent.

<span>Assuming that there is the same amount  of solution X for each reactant</span>

1.0 M NaOH ( X ) = 1.0 moles NaOH

1.00 x 10-5 M C25N3H30Cl ( X ) = 1.00 x 10-5 moles C25N3H30Cl

<span>The result showed that the crystal violet has lesser amount than NaOH. Thus, the limiting reactant in this chemical reaction is crystal violet and the excess reactant is NaOH.</span>

3 0
2 years ago
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