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Archy [21]
2 years ago
5

The diagram above contains contradictory information. Explain the contradiction.

Mathematics
2 answers:
Anarel [89]2 years ago
6 0
Since these are alternate interior angles, they should be congruent. Equating the measures given:
-x - 30 = 5x - 30
x = 0
However, this is not true, since the diagram clearly shows that there is a positive angle between them.
The best answer is choice B.
Usimov [2.4K]2 years ago
4 0

Answer:

Either A or D

Step-by-step explanation:

Both B and C don't work so try these 2

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In the given the figure above, m∠BAC = 64° and m∠CBA = 56°. Part I: Find the m∠DEC. Part II: Explain the steps you took to arriv
Alex17521 [72]

since the triangles are similar

angle DEC = 60 degrees


3 angles inside a triangle equal 180 degrees

BAC = DCE = 64

CBA = EDC = 56

DEC = 180 -56 -64 = 60 degrees


used angle-angle theorem 

6 0
2 years ago
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Erik and Nita are playing a game with numbers. In the game, they each think of a random number from zero to 20. If the differenc
Mademuasel [1]
Let X is the random number Erik thinks of, and Y is the random number Nita thinks of.
Both X and Y are in the range from 0 to 20.
<span>X<=20
Y<=20
If the difference between their two numbers is less than 10, then Erik wins.
The difference between the two numbers can be written X-Y, or Y-X depending on which number (X or Y) is greater. But we do not know that. In order not to get negative value, we calculate absolute value of X-Y,  written |X-Y| which will give positive value whether X is greater than Y or not.
If |X-Y|<10 Erik wins.
</span><span>If the difference between their two numbers is greater than 10, then Nita wins. 
</span><span>If |X-Y|>10 Nita Wins

</span>
6 0
2 years ago
For an outdoor track meet to be cancelled, the temperature, t, outside must be colder than 35 degrees. Complete the following in
qwelly [4]

Answer: I'm pretty sure it would be -7º Celcius for it to be cancelled. Hope it helped!

7 0
2 years ago
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For the total population of a large southern city, mean family income is $34,000, with a standard deviation (for the population)
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See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se
REY [17]

Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 6, p = 0.2

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if P(X \geq 5) < 0.05

We have that

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05

Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

5 0
2 years ago
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