<span>The Java code below will ask for two integers and display the sum. If a non-integer is submitted the code will ask again. The break is used to exit the while true loop indicating that no-errors had occurred and two numbers were added.
System.out.print("Please insert two integers and this will display the sum.");
int numOne;
int numTwo;
while (True) {
try{
System.out.print("Integer Number One? ");
numOne = input.nextInt();
System.out.print("Integer Number Two? ");
numTwo = input.nextInt();
System.out.print("The Sum Is: " + (numOne + numTwo));
break;
}
catch (InputMismatchException e) {
System.out.print("please enter an integer .");
}
}</span>
Answer:
standard deviation of these expected returns = 0.0295 or 2.95%
Step-by-step explanation:
The detailed step is shown in the attachment
Answer:
Step-by-step explanation:
In the normal distribution curve, the mean is in the middle and each line to the left and to the right of that mean represent 1- and 1+ the standard deviation. If our mean is 400, then 400 + 50 = 450; 450 + 50 = 500; 500 + 50 = 550. Going from the mean to the left, we subtract the standard deviation and 400 - 50 = 350; 350 - 50 = 300; 300 - 50 = 250. We are interested in the range that falls between 350 and 450 as a percentage. That range represents the two middle sections, each containing 34% of the data. So the total percentage of response times is 68%. We are looking then for 68% of the 144 emergency response times in town. .68(144) = 97.92 or 98 emergencies that have response times of between 350 and 450 seconds.
Answer:

Step-by-step explanation:

Step 1: Divide the numbers

Step 2: Simplify

Step 3: Simplify

Therefore, the simplified answer is 