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yanalaym [24]
2 years ago
13

Write the electronic configurations for mn, mn2+, mn4+, mn6+, and mn7+

Chemistry
1 answer:
mariarad [96]2 years ago
3 0

<u>Answer:</u> The electronic configurations are written below.

<u>Explanation:</u>

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.  Number of electrons in an atom is determined by the atomic number of that atom.

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

We know that:

Atomic number of Manganese = 25 = Number of protons

Number of electrons = Number of protons - charge

  • <u>For Mn-atom</u>

Number of electrons = 25

Electronic configuration of Mn : 1s^22s^22p^63s^23p^64s^23d^5

  • <u>For Mn^{2+} ion:</u>

Number of electron = 25 - (+2) = 23

Electronic configuration of Mn^{2+}:1s^22s^22p^63s^23p^63d^5

  • <u>For Mn^{4+} ion:</u>

Number of electron = 25 - (+4) = 21

Electronic configuration of Mn^{4+}:1s^22s^22p^63s^23p^63d^3

  • <u>For Mn^{6+} ion:</u>

Number of electron = 25 - (+6) = 19

Electronic configuration of Mn^{6+}:1s^22s^22p^63s^23p^63d^1

  • <u>For Mn^{7+} ion:</u>

Number of electron = 25 - (+7) = 18

Electronic configuration of Mn^{7+}:1s^22s^22p^63s^23p^6

Hence, the electronic configurations are written above.

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The human body is 0.0040% iron. How many milligrams of iron does a 165 pound person contain?​
Fofino [41]

Answer:

in a body of 165 pounds, the iron content is 2993.707 mg

Explanation:

  • % iron = 0.0040% = (mass iron / mass human) * 100

⇒ mass iron / mass human = 4 E-5

∴ mass human = 165 pounds

⇒ mass iron = 165 pounds * 4 E-5

⇒ mass iron = 6.6 E-3 pounds * ( 453.592 g/pound ) * ( 1000 mg/g )

⇒ mass iron = 2993.707 mg iron

8 0
2 years ago
Olympic cyclist fill their tires with helium to make them lighter. Calculate the mass of air in an air filled tire and the mass
inn [45]

<u>Answer:</u> The mass difference between the two is 7.38 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure = 125 psi = 8.50 atm    (Conversion factor:  1 atm = 14.7 psi)

V = Volume = 855 mL = 0.855 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

8.50atm\times 0.855L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{8.50\times 0.855}{0.0821\times 298}=0.297mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For air:</u>

Moles of air = 0.297 moles

Average molar mass of air = 28.8 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of air}}{28.8g/mol}\\\\\text{Mass of air}=(0.297mol\times 28.8g/mol)=8.56g

Mass of air, m_1 = 8.56 g

  • <u>For helium gas:</u>

Moles of helium = 0.297 moles

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of helium}}{4g/mol}\\\\\text{Mass of helium}=(0.297mol\times 4g/mol)=1.18g

Mass of helium, m_2 = 1.18 g

Calculating the mass difference between the two:

\Delta m=m_1-m_2

\Delta m=(8.56-1.18)g=7.38g

Hence, the mass difference between the two is 7.38 grams.

5 0
2 years ago
Hydrogen chloride gas can be prepared by the following reaction: 2NaCl(s) + H2SO4(aq) → 2HCl(g) + Na2SO4(s) How many grams of HC
SVETLANKA909090 [29]

Answer:

The correct answer is is option B

b. 93.3 g

Explanation:

SEE COMPLETE QUESTION BELOW

Hydrogen chloride gas can be prepared by the following reaction: 2NaCl(s) + H2SO4(aq) → 2HCl(g) + Na2SO4(s)

How many grams of HCl can be prepared from 2.00 mol H2SO4 and 2.56 mol NaCl?

a. 7.30 g

b. 93.3 g

c. 146 g

d. 150 g

e. 196 g

CHECK THE ATTACHMENT FOR STEP BY STEP EXPLANATION

7 0
2 years ago
Choose the answer in which the three atoms and/or ions are listed in order of increasing EXPECTED size (smallest particle listed
svp [43]

Answer:

Ar < Cl - < S2-

Explanation:

All the species written above are isoelectronic. This means that they all possess the same number of electrons. All the species above possess 18 electrons, the noble gas electron configuration.

However, for isoelectronic species, the greater the atomic number of the specie, the smaller it is. This is because, greater atomic number implies that their are more protons in the nucleus exerting a greater attractive force on the electrons thereby making the specie smaller in size due to high electrostatic attraction.

8 0
2 years ago
On a clear day at sea level, with a temperature of 25 °C, the partial pressure of N2 in air is 0.78 atm and the concentration of
joja [24]

Answer : The partial pressure of nitrogen gas is, 2.94 atm

Explanation:

According top the Henry's Law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas.

C\propto P

C=K_H\times P

K_H is Henry's constant.

or,

\frac{C_1}{C_2}=\frac{P_1}{P_2}

where,

C_1 = initial concentration of gas = 5.3\times 10^{-4}M

C_2 = final concentration of gas = 2.0\times 10^{-3}M

P_1 = initial partial pressure of gas = 0.78 atm

P_2 = final partial pressure of gas = ?

Now put all the given values in the above formula, we get the final partial pressure of the gas.

\frac{5.3\times 10^{-4}M}{2.0\times 10^{-3}M}=\frac{0.78atm}{P_2}

P_2=2.94atm

Therefore, the partial pressure of nitrogen gas is, 2.94 atm

5 0
2 years ago
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